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2 years ago

A bike travels 4 miles in half an hour, what is its speed?

Physics

1 answer:

omeli [17]2 years ago

3 0

Answer:

8 mph

Explanation:

4 miles in half hour so you add 4 more for the second half

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The energy of a photon is E=\frac{hc}{\lambda}E = h c λ where c is the speed of light and h is a constant known as Planck's cons

Basile [38]

Answer: As a red photon has a twice of the wavelegth to the violet photon then the red photon has half energy of the violet photon.

Explanation: In order to explain the above statement we have to consider the Plack postulate where the energy of photons depend directely of the frequency . As the wavelength and frequency are related by :

c= λ*υ c is the speed of light, λ is the wavelength and υ the frequency of the photon

so the energy of photons are inversely proportional to the wavelength.

As a consequence twice wavelengtht means half energy for the photon.

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3 years ago

How do you calculate Friction force without the coefficient of friction

nadezda [96]

Https://youtu.be/F_DEsMO_Wq8

hope this helped : )

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3 years ago

Find the density of seawater at a depth where the pressure is 680 atm if the density at the surface is 1030 kg/m3. Seawater has

Pie

Answer:

$1060.41kg/m^3$

Explanation:

Bulk modulus is defined as the relative change in the volume of a body produced by a unit of compressive acting uniformly over its surface:

$B=\rho _o \frac{\bigtriangleup P }{\bigtriangleup \rho}$

Hence the density of the seawater at a depth of 680atm is calculated as:-

$\rho=\rho_o +\bigtriangleup \rho=\rho_o(1+\frac{\bigtriangleup P}{B})\\\\=1030 \times (1+ \frac{(680-1)\times10^5}{2.3\times 10^9})\\=1060.41kg/m^3$

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3 years ago

During a chemical reaction, some substances are completely consumed while others my not be. What is the substance that is comple

LUCKY_DIMON [66]

Answer:

It is Limiting Reactant

Explanation:

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2 years ago

A (20*20) cm² loop has a resistance of 0.10 Ω. A magnetic field perpendicular to the loop is B = 4t - 2t², where B is in tesla a

Ilya [14]

Answer with Explanation:

We are given that

Area of loop= $(20\times 20) cm^2=400\times 10^{-4} m^2$

$1 cm^2=10^{-4} m^2$

Resistance, R= $0.1\Omega$

B= $4t-2t^2$

We know that magnetic flux

$\phi=BA$

Emf , $E=\mid \frac{d\phi}{dt}\mid =\mid\frac{d(BA}{dt}\mid =\mid A\frac{dB}{dt}=400\times 10^{-4}\times \frac{4t-2t^2}{dt}\mid =\mid400\times 10^{-4}\times(4-4t)\mid$