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dusya [7]
3 years ago
8

Can anything block a magnet's force feild?

Physics
1 answer:
SVEN [57.7K]3 years ago
7 0
Something that is not magnetic
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How can the speed of solvent molecules be slowed down?
jarptica [38.1K]

Answer:

Explanation:

lower the temperature  -the  higher the temp the more energy the molecules absorb.  The more energy they have the more they move

4 0
3 years ago
How much force is required to accelerate a 0.10 gram mosquito at 20m/?
EastWind [94]

Answer:  0.002 newtons

===================================================

Work Shown:

I'm assuming you meant to write "at 20 m/s^2" at the end. If so, then,

0.10 grams = 0.10/1000 = 0.0001 kg

m = 0.0001 kg = mass

a = 20 m/s^2 = acceleration

F = ma .... newton's second law

F = 0.0001*20

F = 0.002

The force required is 0.002 newtons

8 0
3 years ago
Read 2 more answers
Please can anybody tell me what is this lab equipment​
Umnica [9.8K]

Answer:

hii there

its a test tube holder

Explanation:

hope it helps

5 0
3 years ago
During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive
olganol [36]

Answer:

The force is     F_c  =  789.03 \  N    

Explanation:

From the question we are told that

   The tangential  resistive force is F_t  =   115 \ N

   The mass of the wheel is  m  = 1.80 kg

  The diameter of the wheel is  d =  50.0 cm  = 0.5 \ m

   The diameter of the sprocket is  d_c  =  8.50 \ cm =0.085 \ m

  The angular acceleration considered is  \alpha  =  4.30\ rad/s^2

Generally the radius of the wheel is

       r = \frac{d}{2}

=>     r = \frac{0.5}{2}

=>     r = 0.25 \ m

Generally the radius of the sprocket is

       r_c = \frac{d_c}{2}

=>     r_c = \frac{0.085}{2}

=>     r_c = 0.0425 \ m

Generally the moment of inertia of the wheel is mathematically represented as

      I  =  m  *  r^2

=>    I  =  1.80  *  0.25^2

=>    I  = 1.1125 \ kg \cdot m^2

Generally the torque experienced by the wheel due to the forces acting on it  is mathematically represented as

      \tau =  F_c *  r_c  -  F_t  * r

Here  F_c is the force acting on the sprocket

So  

      \tau =  F_c *  0.0425 - 115  * 0.25

       \tau = 0.0425F_c  -  28.75

Generally the torques that will cause the wheel to move with \alpha  =  4.30\ rad/s^2 is mathematically represented as

       \tau  =  I  * \alpha

So

        0.0425F_c  -  28.75  =   I  * \alpha

        0.0425F_c  -  28.75  =   1.1125  *4.30    

       0.0425F_c  -  28.75  =   1.1125  *4.30    

        F_c  =  789.03 \  N    

5 0
3 years ago
THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!!
poizon [28]

Answer:

391.67Hz

Explanation:

The fundamental frequency formula in string is expressed as;

Fo = V/2L

V is the velocity of the wave = 329m/s

L is the length of the string = 42cm = 0.42m

Substitute

Fo = 329/2(0.42)

Fo = 329/0.84

Fo = 391.67Hertz

Hence the  fundamental frequency of a mandolin string is 391.67Hz

4 0
3 years ago
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