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dusya [7]
3 years ago
8

Can anything block a magnet's force feild?

Physics
1 answer:
SVEN [57.7K]3 years ago
7 0
Something that is not magnetic
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CISTU U
marusya05 [52]

solution:

radius of steel ball(r)=5cm=0.05m

density of ball =8000kgm

terminal velocity(v)=25m/s^2

density of air( d) =1.29 kgm

now

volume of ball(V)=4/3pir^3=1.33×3.14×0.05^3=0.00052 m^3

density of ball= mass of ball/Volume of ball

or, 8000=m/0.00052

or, m=4.16 kg

weight of the ball (W)= mg=4.16×10=41.6 N

viscous force(F)=6 × pi × eta × r × v

=6×3.14×eta×0.05×25

=23.55×eta

To attain the terminal velocity,

Fiscous force=Weight

or, 23.55× eta = 41.6

or, eta = 1.76

whete eta is the coefficient of viscosity.

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Nuclear power plants, wind farms, water farms, and geothermal heating
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yaroslaw [1]

The AREA of the shaded region is the moving object's displacement.

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What foxes need to eat to<br> stay alive​
11Alexandr11 [23.1K]

Answer:

<h3>They eat meat and vegetation. </h3>
8 0
3 years ago
Read 2 more answers
The block shown above has a mass of 105 g.<br> What is the density of the block? SC.8.P.8.3
zaharov [31]

The density of the block is 1.25 cm³

The correct answer to the question is Option B. 1.25 cm³

To solve this question, we'll begin by calculating the volume of the block. This can be obtained as follow:

Length = 7 cm

Height = 4 cm

Width = 3 cm

<h3>Volume =? </h3>

Volume = Length × Width × Height

Volume = 7 × 3 × 4

<h3>Volume = 84 cm³</h3>

Thus, the volume of the block is 84 cm³

Finally, we shall determine the density of the block. This can be obtained as follow:

Density is defined as mass per unit volume i.e

Density = \frac{mass}{volume} \\\\

Mass of block = 105 g

Volume of block = 84 cm³

<h3>Density of block =? </h3>

Density = \frac{mass}{volume}\\\\Density = \frac{105}{84}\\\\

<h3>Density of block = 1.25 cm³</h3>

Therefore, the density of the block is 1.25 cm³.

Hence, Option B. 1.25 cm³ gives the correct answer to the question.

Learn more: brainly.com/question/2040396?referrer=searchResults

4 0
2 years ago
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