solution:
radius of steel ball(r)=5cm=0.05m
density of ball =8000kgm
terminal velocity(v)=25m/s^2
density of air( d) =1.29 kgm
now
volume of ball(V)=4/3pir^3=1.33×3.14×0.05^3=0.00052 m^3
density of ball= mass of ball/Volume of ball
or, 8000=m/0.00052
or, m=4.16 kg
weight of the ball (W)= mg=4.16×10=41.6 N
viscous force(F)=6 × pi × eta × r × v
=6×3.14×eta×0.05×25
=23.55×eta
To attain the terminal velocity,
Fiscous force=Weight
or, 23.55× eta = 41.6
or, eta = 1.76
whete eta is the coefficient of viscosity.
Nuclear power plants, wind farms, water farms, and geothermal heating
The AREA of the shaded region is the moving object's displacement.
Answer:
<h3>They eat meat and vegetation. </h3>
The density of the block is 1.25 cm³
The correct answer to the question is Option B. 1.25 cm³
To solve this question, we'll begin by calculating the volume of the block. This can be obtained as follow:
Length = 7 cm
Height = 4 cm
Width = 3 cm
<h3>Volume =? </h3>
Volume = Length × Width × Height
Volume = 7 × 3 × 4
<h3>Volume = 84 cm³</h3>
Thus, the volume of the block is 84 cm³
Finally, we shall determine the density of the block. This can be obtained as follow:
Density is defined as mass per unit volume i.e

Mass of block = 105 g
Volume of block = 84 cm³
<h3>Density of block =? </h3>

<h3>Density of block = 1.25 cm³</h3>
Therefore, the density of the block is 1.25 cm³.
Hence, Option B. 1.25 cm³ gives the correct answer to the question.
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