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jok3333 [9.3K]
3 years ago
11

If a car has a mass of 200 kilograms and produces a force of 500 N, how fast will the car accelerate?

Physics
2 answers:
Andrej [43]3 years ago
6 0

Explanation:

F = ma

500N = 200 × a

200a. = 500N

a. =. 2.5m/s²

PLEASE GIVE BRAINLIEST.

Hitman42 [59]3 years ago
3 0

Answer:

2.5m/s²

Explanation:

Given parameters:

Mass of car  = 200kg

Force on car  = 500N

Unknown:

Acceleration of the car  = ?

Solution:

According to Newton's second law of motion:

      Force  = mass x acceleration

Insert the given parameters and find the acceleration;

         500  = 200 x acceleration

           acceleration = 2.5m/s²

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Read 2 more answers
The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 22
alexgriva [62]
1) The law of motion of the projectile is
h(t) = 2+22.5 t-4.9 t^2
To find the velocity, we should compute the derivative of h(t):
v(t)=h'(t)=22.5-2\cdot 4.9t=22.5-9.8t
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v(2.0s)=22.5-9.8\cdot2.0 =2.9 m/s
v(4.0s)=22.5-9.8\cdot 4.0s=-16.7 m/s
The negative sign in the second speed means the projectile has already reached its maximum height and it is now going downward.

2) The projectile reaches its maximum height when the speed is equal to zero:
v(t)=0
So we have
22.5-9.8 t=0
And solving this we find
t=2.30 s

3) To find the maximum height, we take h(t) and we just replace t with the time at which the projectile reaches the maximum height, i.e. t=2.30 s:
h(2.30 s)=2+22.5\cdot 2.30 -4.9 \cdot (2.30s)^2 = 27.83 m

4) The time at which the projectile hits the ground is the time at which the height is zero: h(t)=0. So, this translates into
2+22.5t -4.9 t^2 = 0
This is a second-order equation, and if we solve it we get two solutions: the first solution is negative, so we can ignore it since it's physically meaningless; the second solution is
t=4.68 s
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5) The velocity of the projectile when it hits the ground is the velocity at time t=4.68 s:
v(4.68 s)=22.5-9.8\cdot 4.68 =-23.36  m/s
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