All categories

2 years ago

A bicycle is in motion. What about the bicycle is changing?

Physics

2 answers:

zhannawk [14.2K]2 years ago

5 0

It’s the engery. you are changing the engery

Ksenya-84 [330]2 years ago

3 0

An object is in motion. That's ALL we know about it.

==> Its location is definitely changing.

==> Its mass, speed, velocity, acceleration, momentum, kinetic energy, potential energy, distance from you, and direction from you may or may not be changing.

You might be interested in

What is the energy of motion.

AlladinOne [14]

Answer:

Is the sum of potential and kinetic energy in an object that is used to do work.

4 0

2 years ago

Read 2 more answers

An electron is released from rest at a distance of 6.00 cm from a proton. If the proton is held in place, how fast will the elec

lana66690 [7]

Answer:

91.87 m/s

Explanation:

Given:

x = initial distance of the electron from the proton = 6 cm = 0.06 m

y = initial distance of the electron from the proton = 3 cm = 0.03 m
u = initial velocity of the electron = 0 m/s

Assume:

m = mass of an electron = $9.1\times 10^{-31}\ kg$
v = final velocity of the electron
e = magnitude of charge on an electron = $1.6\times 10^{-19}\ C$

p = magnitude of charge on a proton = $1.6\times 10^{-19}\ C$

We know that only only electric field due to proton causes to move from a distance of 6 cm from proton to 3 cm distance from it. This means the electric force force does work on the electron to move it from one initial position to the final position which is equal to the change in potential energy of the electron due to proton.

Now, according to the work-energy theorem, the total work done by the electric force on the electron due to proton is equal to the kinetic energy change in it.

$\therefore \textrm{Kinetic energy change}= \textrm{Change in potential energy}\\\Rightarrow \dfrac{1}{2}m(v^2-u^2)= \dfrac{kpe}{y}-\dfrac{kpe}{x}\\\Rightarrow \dfrac{1}{2}m(v^2-(0)^2)= \dfrac{kpe}{0.03}-\dfrac{kpe}{0.06}\\\Rightarrow \dfrac{1}{2}mv^2= \dfrac{100kpe}{3}-\dfrac{100kpe}{6}\\\Rightarrow \dfrac{1}{2}mv^2= \dfrac{100kpe}{6}\\$

$\Rightarrow v^2= \dfrac{100kpe\times 2}{6m}\\\Rightarrow v^2= \dfrac{100kpe}{3m}\\\Rightarrow v^2= \dfrac{100\times 9\times 10^9\times 1.6\times 10^{-19}\times 1.6\times 10^{-19}}{3\times 9.1\times 10^{-31}}\\\Rightarrow v^2=8.44\times 10^3\\\Rightarrow v=91.87\ m/s\\$

Hence, when the electron is at a distance of c cm from the proton, it moves with a velocity of 91.87 m/s.

8 0

3 years ago

If the vertical component of velocity for a projectile is 7.3 meters/second, what is its hang time?

Kamila [148]

A projectile motion is characterized by motion moving in a direction of an arc. It is acted upon by two component vectors: the horizontal and vertical. These two vectors are independent of each other when it comes to time of flight. The horizontal direction travels at constant speed, while the vertical direction travels at constant acceleration due to gravity, The time for an object to reach the ground would be equal, whether dropped from the sampe point or thrown in a projectile motion. Of course, this is assuming ideality wherein there is no air resistance.

So, the hang up time, or the time the object stayed on air is calculated using this equation:

a = Δv/t
Δv is the change in velocity which is the initial velocity when it was dropped to when it reaches zero velocity when it hits the ground.
9.81 m/s² = |(0 - 7.3)|/t
t = 0.744 seconds

6 0

3 years ago

What 2 things do you need to make sound? help ASAP

inessss [21]

Answer:

- A vibrating object

- a medium to travel

HOPE IT HELPS :)

PLEASE MARK IT THE BRAINLIEST!

8 0

3 years ago

Why does a skier wear polarized glasses instead of glasses that are used for reading?

Afina-wow [57]

A skier wears polarized glasses instead of glasses that are used for reading because polarized glasses decrease reflected glare compared to regular glasses. (D)

Hope this answers your question correctly.

8 0

2 years ago

Read 2 more answers