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Vanyuwa [196]
3 years ago
14

.An airplane accelerates down a runway at

Physics
1 answer:
solniwko [45]3 years ago
6 0

Starting from rest, the plane travels a distance

<em>x</em> = 1/2 <em>at</em>²

with acceleration <em>a</em> after time <em>t</em>. In this instance, it travels

<em>x</em> = 1/2 (3.20 m/s²) (32.8 s)²

<em>x</em> ≈ 1720 m

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Determine the value of the resultant and its location from O.<br>see attach image.​
xxTIMURxx [149]

Answer:

Explanation:

In the x direction the force will be

½(-w₀)L/2 = -¼w₀L  

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½(-w₀)L + ½w₀L/2 = -¼w₀L  

the magnitude of the resultant will be

F = w₀L  √((-¼)² + (-¼)²) = w₀L√⅛

in the direction

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to find the distance, we balance moments

(w₀L√⅛)[d] = ½(w₀)L[⅔L] + ¼w₀L[⅔L/2] - ¼w₀L[L - ⅓L/2]

     (√⅛)[d] = ½         [⅔L] + ¼      [⅔L/2] - ¼      [L - ⅓L/2]

     (√⅛)[d] = ½[⅔L] + ¼[⅔L/2] - ¼[L - ⅓L/2]

     (√⅛)[d] =      ⅓L  +    ⅟₁₂L     -  ¼L + ⅟₂₄L  

     (√⅛)[d] = 5L/24

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               d = 5√⅛L/3

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Answer:

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velocity = wavelength x frequency

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