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Vanyuwa [196]
2 years ago
14

.An airplane accelerates down a runway at

Physics
1 answer:
solniwko [45]2 years ago
6 0

Starting from rest, the plane travels a distance

<em>x</em> = 1/2 <em>at</em>²

with acceleration <em>a</em> after time <em>t</em>. In this instance, it travels

<em>x</em> = 1/2 (3.20 m/s²) (32.8 s)²

<em>x</em> ≈ 1720 m

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A steel marble with 0.05 kg of mass starts from rest and rolls down a ramp. It travels 0.25 m in 1.2 seconds. Find the force act
emmasim [6.3K]

After finding acceleration, it is found that 0.02 N of force is acting on the marble

<h3>What is Force ?</h3>

Force can simply be defined as a pull or push. It is the product of mass and acceleration of the object. It is a vector quantity and it is measured in Newton.

Given that a steel marble with 0.05 kg of mass starts from rest and rolls down a ramp. It travels 0.25 m in 1.2 seconds.

The parameters to consider are;

  • m = 0.05 Kg
  • u = 0
  • s = 0.25 m
  • t = 1.2 s
  • a = ?
  • F = ?

Before we find the force acting on the marble, let us first find the acceleration by using the formula: s = ut + 1/2at²

Substitute all the parameters into the formula

0.25 = 0 + 1/2 × a × 1.2²

0.25 = 1/2 × a × 1.44

0.25 = 0.72a

a = 0.25/0.72

a = 0.35 m/s²

The force acting on the marble will be ;

F = ma

F = 0.05 × 0.35

F = 0.017

F = 0.02 N

Therefore, the force acting on the marble is 0.02 N

Learn more about Force here: brainly.com/question/388851

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3 0
1 year ago
Four astronauts are in a spherical space station. (a) If, as is typical, each of them breathes about 500 cm
mario62 [17]

Answer:

A) if each astronaut breathes about 500 cm³, the total volume of air breathed in a year is 14716.8m³.

B) The Diameter of this spherical space station should be 30.4m

Explanation:

The breathing frequency (according to Rochester encyclopedia) is about 12-16 breath per minute. if we take the mean value (14 breath per minute), we can estimate the total breaths of a person along a year:

f_b=14\frac{br}{min} \cdot \frac{60min}{1hr} \frac{24hr}{1day}\frac{365day}{1year}=29433600\frac{br}{year}

If we multiply this for the number of people in the station and the volume each breath needs, we obtain the volume breathed in a year.

The volume of a sphere is:

V_{sph}=\frac{4\pi}{3}r^3

So the diameter is:

D=2r=2\sqrt[3]{\frac{3V_{sph}}{4\pi}} =30.4m

6 0
2 years ago
A block of mass 10 kg slides down an inclined plane that has an angle of 30. If the inclined plane has no friction and the block
Helga [31]
No friction present means: Ek = Ep

So Ek = mgh = 10 * 9.8 * 2 = 196 J
4 0
3 years ago
Read 2 more answers
elastic wire extend by 1.ocm when a load on 20g range from It, what additional load will it be required Cause the futher extensi
Citrus2011 [14]

Answer:

40g

Explanation:

20g range > 1.0cm

Therefore,

40g range > 2.0cm

6 0
2 years ago
A 1.60 m cylindrical rod of diameter 0.550 cm is connected to a power supply that maintains a constant potential difference of 1
bija089 [108]

1.

Answer:

Part a)

\rho = 1.35 \times 10^{-5}

Part b)

\alpha = 1.12 \times 10^{-3}

Explanation:

Part a)

Length of the rod is 1.60 m

diameter = 0.550 cm

now if the current in the ammeter is given as

i = 18.7 A

V = 17.0 volts

now we will have

V = I R

17.0 = 18.7 R

R = 0.91 ohm

now we know that

R = \rho \frac{L}{A}

0.91 = \rho \frac{1.60}{\pi(0.275\times 10^{-2})^2}

\rho = 1.35 \times 10^{-5}

Part b)

Now at higher temperature we have

V = I R

17.0 = 17.3 R

R = 0.98 ohm

now we know that

R = \rho \frac{L}{A}

0.98 = \rho' \frac{1.60}{\pi(0.275\times 10^{-2})^2}

\rho' = 1.46 \times 10^{-5}

so we will have

\rho' = \rho(1 + \alpha \Delta T)

1.46 \times 10^{-5} = 1.35 \times 10^{-5}(1 + \alpha (92 - 20))

\alpha = 1.12 \times 10^{-3}

2.

Answer:

Part a)

i = 1.55 A

Part b)

v_d = 1.4 \times 10^{-4} m/s

Explanation:

Part a)

As we know that current density is defined as

j = \frac{i}{A}

now we have

i = jA

Now we have

j = 1.90 \times 10^6 A/m^2

A = \pi(\frac{1.02 \times 10^{-3}}{2})^2

so we will have

i = 1.55 A

Part b)

now we have

j = nev_d

so we have

n = 8.5 \times 10^{28}

e = 1.6 \times 10^{-19} C

so we have

1.90 \times 10^6 = (8.5 \times 10^{28})(1.6 \times 10^{-19})v_d

v_d = 1.4 \times 10^{-4} m/s

8 0
3 years ago
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