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sp2606 [1]
3 years ago
9

HURRY

Physics
2 answers:
Lynna [10]3 years ago
8 0

Answer:

the answer is b or "The sound wave will not be generated, so there will be no echoes received."

Explanation:

Mrac [35]3 years ago
6 0

Answer:

It’s b

Explanation:

Everyone else is wrong and I tried this and got it right

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If 53.62 ml of an oil weighs 48.34 g what is the specific gravity of the oil
Maksim231197 [3]
The specific gravity is the ratio of the density of oil to the density of water. Since the density of water is 1g/ml, the density of a substance is numerically the same as the specific gravity.

However, specific gravity is a dimensionless number, while density has units mass/volume.

So, the density of oil is .901 g/ml, but the specific gravity is just .901

In Imperial units, the density of the oil is 56.2 lb/ft^3, but the specific gravity is still .901
3 0
3 years ago
The blades of a fan running at low speed turn at 26.2 rad/s. When the fan is switched to high speed, the rotation rate increases
Lady bird [3.3K]

Answer: 1.79\ rad/s^2

Explanation:

Given

Initial angular speed is \omega_1=26.2\ rad/s

Final angular speed is \omega_2=36.5\ rad/s

Time period t=5.75\ s

Magnitude of the fan's acceleration is given by

\Rightarrow \alpha=\dfrac{\omega_2-\omega_1}{t}

Insert the values

\Rightarrow \alpha=\dfrac{36.5-26.2}{5.75}\\\\\Rightarrow \alpha=\dfrac{10.3}{5.75}\\\\\Rightarrow \alpha=1.79\ rad/s^2

Thus, fan angular acceleration is 1.79\ rad/s^2

8 0
3 years ago
Read 2 more answers
You throw a ball straight up. The ball has an initial speed of 11.2 m/s when it leaves your hand What is the maximum height the
Jet001 [13]

Answer:

Explanation:

Given

initial velocity u=11.2\ m/s

At maximum height velocity of ball is zero

using

v^2-u^2=2as

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

(0)^2 -(11.2)^2=2\times (-9.8)\times (s)

s=\frac{11.2^2}{2\times 9.8}

s=6.4

time taken by the ball to reach the maximum height

v=u+at

0=11.2-9.8\times t

t=\frac{11.2}{9.8}

t=1.142\ s

At t=2\ s height of ball is

h=ut+\\frac{1}{2}at^2

h=11.2\times 2-\frac{1}{2}9.8\times (2)^2

h=22.4-19.6

h=2.8\ m

i.e. ball is moving downward

height at v=5\ m/s

v^2-u^2=2as

s=\frac{25-125.4}{2\times (-9.8)}

s=5.12\ m    

8 0
3 years ago
Why is the mechanical advantage of a bottle opener always greater than 1?
Katen [24]
For a lever, the mechanical advantage is the ratio of the lever arms. Since the lever arm of the opener is always greater than that of the output arm, the mechanical advantage is greater than 1.
6 0
3 years ago
The gas in a cylinder has a volume of 8 liters at a pressure of 109 kPa. The pressure of the gas is increased to 211 kPa. Assumi
user100 [1]
<span>3.9 L  I believe

I hope this helps!</span>
4 0
3 years ago
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