A baseball with a mass of 0.145 kilograms collides with a bat at a velocity of 44 meters/second. The ball bounces off the bat wi
2 answers:
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Answer:
Approximately (assuming that this spring is ideal.)
Explanation:
The displacement of a spring is the new length of the spring relative to the original length.
For example:
- When the
-spring in this question is stretched to
, the displacement is
.
- Likewise, if this spring is stretched to
, the displacement would be
.
If this spring is ideal, the force on the spring would be proportional to the displacement of the spring. In other words, if a force of displaces this spring by
, while a force of
displaces this spring by
, then:
.
In this question, it is given that a force of would stretch this spring by
. Thus, the force
required to stretch this spring by
would satisfy:
.
Rearrange and solve for :
.
Answer:
h = 2.5 m
Explanation:
Given that,
Mass of a ball, m = 1.5 kg
Initial velocity of the ball, u = 7 m/s
We need to find the maximum height reached by the ball. Let it is be h. Using the conservation of energy to find it such that,
Put all the values,
So, it will reach to a height of 2.5 m.