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stealth61 [152]
2 years ago
5

Which set of values could be the side lengths of a 30-60-90 triangle

Mathematics
1 answer:
Mrrafil [7]2 years ago
8 0

Answer:

D. 6, 6\sqrt{3}, 12

Step-by-step explanation:

the Pythagorean Theorem states that a^{2} +b^{2} =c^{2}

so,

6^{2} =36\\(6\sqrt{3}) ^{2} =108\\12^{2} =144\\36+108=144

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4 0
3 years ago
The graph shows the relationship.....
Anna35 [415]

Answer:

Part A: That 6 pounds of rice costs $18

Part B: (1,3) represents the unit price

Part C: 4 pounds of rice, because $12/3 equals 4

Step-by-step explanation:

Part A: The first point, 6, is on the amount of rice axis and the second point, 18, is on the total cost axis.

Part B: The unit price means the price for just 1 of something, so if you go to 1 pound of rice on the graph, you see it's at 3 on the total cost axis. Which means that 1 pound of rice costs $3.

Part C: From Part B you know that 1 pound of rice equals $3. So if you spend $12, then you can divide that by $3 to see how many pounds of rice you bought. 12/3 equals 4, so you bought 4 pounds of rice. Or you can count by 3's until you get to 12: 3, 6, 9, 12. That's 4 times so that means you bought 4 pounds of rice.

5 0
2 years ago
My husband is having problems with this problem it's super hard pls help what's 10-5
Romashka-Z-Leto [24]
10 - 5 = 5 

Hope this helped your husband.
7 0
3 years ago
Read 2 more answers
If f(x)=x2-2x-8 and g(x)=1/4x-1 for which value of x is f(x)=g(x)
fomenos

f(x)=x^2-2x-8;\ g(x)=\dfrac{1}{4}x-1\\\\f(x)=g(x)\iff x^2-2x-8=\dfrac{1}{4}x-1\qquad\text{multiply both sides by 4}\\\\4x^2-8x-32=x-4\qquad\text{subtract x from both sides}\\\\4x^2-9x-32=-4\qquad\text{add 4 to both sides}\\\\4x^2-9x-28=0\\\\4x^2-16x+7x-28=0\\\\4x(x-4)+7(x-4)=0\\\\(x-4)(4x+7)=0\iff x-4=0\ \vee\ 4x+7=0\\\\x=4\ \vee\ 4x=-7\\\\\boxed{x=4\ \vee\ x=-\dfrac{7}{4}}

6 0
3 years ago
The center of a hyperbola is (−4,3) , and one vertex is (−4,7) . The slope of one of the asymptotes is 2.
Monica [59]

Answer:

The answer to your question is below

Step-by-step explanation:

C (-4, 3)

V (-4, 7)

asymptotes = 2 = \frac{b}{a}

- This is a vertical hyperbola, the equation is

       \frac{(y - k)^{2} }{a^{2} } + \frac{(x - h)^{2} }{b^{2} } = 1

slope = 2

a is the distance from the center to the vertex = 4

b = 2(4) = 8

       \frac{(y - 3)^{2} }{4^{2} } + \frac{(x + 4)^{2} }{8^{2} } = 1

       \frac{(y - 3)^{2} }{16} + \frac{(x + 4)^{2} }{64} = 1

7 0
3 years ago
Read 2 more answers
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