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2 years ago

Chromosomes are a form of blood cells.

Physics

2 answers:

Inessa05 [86]2 years ago

8 0

Answer:

false im just trying to get it if you'd like to give it to me

s344n2d4d5 [400]2 years ago

5 0

The answer is false :)

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The process in which acids and bases react so that the properties of both are lost to form water and a salt is called __________

makvit [3.9K]

The process is called neutralization.
Hope this helps!

4 0

2 years ago

Lin Yao looks at the back of a spoon. How should she describe her reflection?

Cerrena [4.2K]

The correct answer is C, right-side up and smaller.

It is the most common example of spherical mirrors. The inside of the spoon acts like a concave mirror and the back side of it like a convex mirror.

A convex mirror always forms a real and diminished image. That is, the image formed is erect or right-side up and smaller in size. Therefore, Lin Yao should describe her reflection on the back side of the mirror to be right-side up and smaller.

6 0

3 years ago

Read 2 more answers

A bus initially moving at 20 m/s with an acceleration of -4m/s² for 5

Alborosie

Answer:

50m; 0m/s.

Explanation:

Given the following data;

Initial velocity = 20m/s

Acceleration, a = - 4m/s²

Time, t = 5secs

To find the displacement, we would use the second equation of motion;

$S = ut + \frac {1}{2}at^{2}$

Substituting into the equation, we have;

$S =20*5 + \frac{1}{2}*(-4)*5^{2}$

$S =100 + (-2)*25$

$S =100 - 50$

S = 50m

Next, to find the final velocity, we would use the third equation of motion;

$V^{2} = U^{2} + 2aS$

Where;

V represents the final velocity measured in meter per seconds.

U represents the initial velocity measured in meter per seconds.

a represents acceleration measured in meters per seconds square.

<em>Substituting into the equation, we have;</em>

$V^{2} = 20^{2} + 2(-4)*50$

$V^{2} = 400 - 400$

$V^{2} = 0$

V = 0m/s

<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>

5 0

2 years ago

: The truck is to be towed using two ropes. Determine the magnitudes of forces FA and FB acting on each rope in order to develop

Sholpan [36]

Answer:

Fa=774 N

Fb=346 N

Explanation:

We will solve this problem by equating forces on each axis.

On x-axis let forces in positive x-direction be positive and forces in negative x-direction be negative
On y-axis let forces in positive y-direction be positive and forces in negative y-direction be negative

While towing we know that car is mot moving in y-direction so net force in y-axis must be zero

⇒∑Fy=0

⇒ $Fa*sin(50)-Fb*sin(20)=0$