Answer:
and ![44.08^{\circ}](https://tex.z-dn.net/?f=44.08%5E%7B%5Ccirc%7D)
and ![25.77^{\circ}](https://tex.z-dn.net/?f=25.77%5E%7B%5Ccirc%7D)
Explanation:
= Wavelength
= Angle
m = Order
Distance between grating is given by
![d=\dfrac{1}{5300}\\\Rightarrow d=0.0001886\ \text{cm}](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7B1%7D%7B5300%7D%5C%5C%5CRightarrow%20d%3D0.0001886%5C%20%5Ctext%7Bcm%7D)
![\lambda=656\ \text{nm}](https://tex.z-dn.net/?f=%5Clambda%3D656%5C%20%5Ctext%7Bnm%7D)
We have the relation
![d\sin\theta=m\lambda\\\Rightarrow \theta=\sin^{-1}\dfrac{m\lambda}{d}](https://tex.z-dn.net/?f=d%5Csin%5Ctheta%3Dm%5Clambda%5C%5C%5CRightarrow%20%5Ctheta%3D%5Csin%5E%7B-1%7D%5Cdfrac%7Bm%5Clambda%7D%7Bd%7D)
m = 1
![\theta=\sin^{-1}\dfrac{1\times 656\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=20.35^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D%5Csin%5E%7B-1%7D%5Cdfrac%7B1%5Ctimes%20656%5Ctimes%2010%5E%7B-9%7D%7D%7B0.0001886%5Ctimes%2010%5E%7B-2%7D%7D%5C%5C%5CRightarrow%20%5Ctheta%3D20.35%5E%7B%5Ccirc%7D)
m = 2
![\theta=\sin^{-1}\dfrac{2\times 656\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=44.08^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D%5Csin%5E%7B-1%7D%5Cdfrac%7B2%5Ctimes%20656%5Ctimes%2010%5E%7B-9%7D%7D%7B0.0001886%5Ctimes%2010%5E%7B-2%7D%7D%5C%5C%5CRightarrow%20%5Ctheta%3D44.08%5E%7B%5Ccirc%7D)
The first and second order angular deflection is
and ![44.08^{\circ}](https://tex.z-dn.net/?f=44.08%5E%7B%5Ccirc%7D)
![\lambda=410\ \text{nm}](https://tex.z-dn.net/?f=%5Clambda%3D410%5C%20%5Ctext%7Bnm%7D)
m = 1
![\theta=\sin^{-1}\dfrac{1\times 410\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=12.56^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D%5Csin%5E%7B-1%7D%5Cdfrac%7B1%5Ctimes%20410%5Ctimes%2010%5E%7B-9%7D%7D%7B0.0001886%5Ctimes%2010%5E%7B-2%7D%7D%5C%5C%5CRightarrow%20%5Ctheta%3D12.56%5E%7B%5Ccirc%7D)
m = 2
![\theta=\sin^{-1}\dfrac{2\times 410\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=25.77^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D%5Csin%5E%7B-1%7D%5Cdfrac%7B2%5Ctimes%20410%5Ctimes%2010%5E%7B-9%7D%7D%7B0.0001886%5Ctimes%2010%5E%7B-2%7D%7D%5C%5C%5CRightarrow%20%5Ctheta%3D25.77%5E%7B%5Ccirc%7D)
The first and second order angular deflection is
and
.
Answers:
The acceleration due to gravity on the surface of earth is 9.8 ms^(-2).Time period of a simple pendulum on earth and moon are 3.5 second and 8.4 second respectively. Find the acceleration due to gravity on the moon . <br> Hint : T_(e) = 2pi sqrt((L)/(g_(e))) T_(m)= 2pi sqrt((L)/(g_(m))) <br> (T_(e)^(2))/(T_(m)^(2))= (g_(m))/(g_(e)) <br> g_(m) = (T_(e)^(2))/(T_(m)^(2))g_(e)
Explanation:
Look, if you want to connect the capacitors parallel which the question wants you to do so, first
C1+C2=Ct
0.22μF+470μF
470.22μF
then you got the formula
C=Q/V===> Qt=CV===>
470.22×10‐⁶×60= do the calculations and it's yours
10mm=1cm
So..........
275 mm=27.5 cm
Answer:
Force of the ball against the bat
Explanation:
Newton's third law of motion states that for every action, there is an equal and opposite reaction. When a player hits a ball with a bat, the force the player exerted on the ball through the bat gave the ball a push force in the forward direction. This is an action force. Now that an action has been initiated, there must be a reaction according to Newton's third law of motion. The magnitude of the force on the ball equals the magnitude of the force on the bat. The direction of the force on the ball is opposite to the direction of the force on the ball. The ball will give the bat an equal and opposite force trying to push the bat backward by resisting the impact of the bat. This is the reaction. The ball will only move if the applied force is able to overcome the resisting force by the bat.
Where;
is the action force of the bat against the ball.
is the equal and opposite reaction force of the ball towards the ball.