Answer:
0.25 kg m^2
Explanation:
mass of each , m = 500 g = 0.5 kg
distance, r = 50 cm = 0.5 m
Moment of inertia about the axis passing through one corner and perpendicular to the plane of triangle
I = mr^2 + mr^2
I = 2 mr^2
I = 2 x 0.5 x 0.5 x 0.5
I = 0.25 kgm^2
We'll assume that the whole scene takes place on Earth.
So the acceleration of gravity is 9.8 m/s² downward.
a). Gravity makes anything fall 9.8 m/s faster every second.
That's the same thing as rising 9.8 m/s slower every second.
If it takes 2.9 seconds to reach its maximum height, then
it must have started out rising at (9.8 x 2.9) = 28.4 m/s.
b). The ball left the bat at 28.4 m/s.
After 2.9 seconds, its speed was zero. (That's why it started falling.)
It's average speed during the climb was
1/2 (28.4 + 0) = 14.2 m/s .
It rose straight up at an average speed of 14.2 m/s for 2.9 seconds,
so it reached a maximum height of
(14.2 x 2.9) = 41.2 meters .
Answer:
D.The potential energy per unit charge
Explanation:
Electric potential of a charged particle:
It is scalar quantity because it has magnitude but it does not have direction.
It is the amount of work done required to move a unit positive charge from reference point to specific point in the electric field without producing any acceleration.
Mathematical representation:

Where W= Work done
= Unit positive charge
Other formula to calculate electric field:

Where K=
It can be defined as potential energy per unit charge.
Hence, option D is true.
High mass are largest , hotest , and brightest sequence
Answer:
510 m
Explanation:
The arrow is fired upward, so the motion of the arrow is a free fall motion, therefore we can find the maximum height by using the suvat equation
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
Here we have:
v = 0 (at the point of maximum height, the velocity of the arrow is zero)
u = 100 m/s (initial velocity)
(acceleration of gravity, downward)
s = ? is the maximum height
Solving for s, we find the maximum height of the arrow:
