Question

Help i’m timed pllzzzzz

Answer 1

Answer:

$a = p*q\\b = (p*s)+(q*r)\\c = r*s$

Step-by-step explanation:

The standard form of trinomial is given as:

$ax^2+bx+c$

And the factored form is:

$(px+r)(qx+s)$

In order to find the values of a,b and c in terms of p,q,r and s we will take the factored form, multiply it and then compare it with the standard form.

So,

$(px+r)(qx+s)\\=px(qx+s)+r(qx+s)\\= pqx^2+psx+qrx+rs\\= pqx^2+(ps+qr)x+rs$

Now comparing it with the standard form of trinomial

We will compare the co-efficients of x^2, x and the constant

By comparing, we get

$a = pq = p*q\\b = ps+qr = (p*s)+(q*r)\\c = rs = r*s$

Hence,

$a = p*q\\b = (p*s)+(q*r)\\c = r*s$