Answer:
2Fe + 3Cl2 → 2FeCl3
Explanation:
Fe + Cl2 —> FeCl3
There are 3atoms of Cl on the right side and 2 atoms on the left side. Therefore, to balance Cl put 2 in front of FeCl3 and put 3 in front of Cl2 as shown below:
Fe + 3Cl2 → 2FeCl3
Now, we see clearly that there are 2 atoms of Fe on the right side and 1 on the left side. This can be balanced by putting 2 in front of Fe as shown below:
2Fe + 3Cl2 → 2FeCl3
Now the equation is balanced.
Answer:
102.58 cal.
Explanation:
Given data:
Mass of mercury = 622 g
Initial temperature = 37°C
Final temperature = 42°C
Specific heat capacity of mercury = 0.138 J/g.°C
Energy required = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 42°C - 37°C
ΔT = 5°C
Q = 622 g × 0.138 J/g.°C × 5°C
Q = 429.18 J
J to cal:
429.18 J × 1 cal /4.184 j
102.58 cal.
Answer:
-514 kJ/mol
Explanation:
The bond enthalpy which is also known as bond energy can be defined as the amount of energy needed to split one mole of the stated bond. The change in enthalpy of a given reaction can be estimated by subtracting the sum of the bond energies of the reactants from the sum of the bond energies of the products.
For the given chemical reaction, the change in enthalpy of the reaction is:
Δ [2(409) + 4(388) + 3(496) - 4(630) - 4(463)] kJ/mol = 818 + 1552 + 1488 - 2520 - 1852 = -514 kJ/mol
The compound is found to be 13.068% C and 86.932% Br so
the molecular formula is CBr. The geometry
around the carbon atom is just linear. And the compound formed is polar due to
the electronegativity of the bromine atom attached to the carbon atom.