Answer:
i. Molar mass of glucose = 180 g/mol
ii. Amount of glucose = 0.5 mole
Explanation:
<em>The volume of the glucose solution to be prepared</em> = 500 
<em>Molarity of the glucose solution to be prepared</em> = 1 M
i. Molar mass of glucose (
) = (6 × 12) + (12 × 1) + (6 × 16) = 180 g/mol
ii.<em> mole = molarity x volume</em>. Hence;
amount (in moles) of the glucose solution to be prepared
= 1 x 500/1000 = 0.5 mole
Answer:
Most likely N or S it might not be safe but that is what experiments do I guess.
Explanation:
Alpha partical is a He nucleus. When decaying alpha particle mass is reduced by 4 and atomic number is reduced by 2.
The actual element which has 102 protons is No (Nobelium).
Since it has 167 neutrons, the mass = protons + neutrons = 102 + 167 = 269
after an alpha decay, the new element formed has 100 protons which is Fm ( Fermium)
the alpha decaying equation is,
₁₀₂²⁶⁹No → ₁₀₀²⁶⁵Fm + ₂⁴α + heat
the total mass and the atomic number( numbe rof protons) must be equal in both sides.
Answer:
338.00 mL
Explanation:
The lead ions come from the salt Pb(NO₃)₂ and the iodide from the acid HI, so the balanced reaction is:
Pb(NO₃)₂(aq) + 2HI(aq) → PbI₂(s) + 2HNO₃(aq)
So, the stoichiometry is 1 mol of Pb(NO₃)₂ to 2 moles of HI, then:
1 mol of Pb(NO₃)------------------------------------ 2 moles of HI
0.600 mol of Pb(NO₃)₂--------------------------- x
By a simple direct three rule:
x = 1.200 mol of HI
The acid has concentration equal to 3.550 mol/L, the volume (V) is the number of moles divided by the molar concentration:
V = 1.200/3.550 = 0.338 L
V = 338.00 mL