KF = 8 units ( 16/2 = 8)
Angle DEK = 88 degrees ( 44 x 2 = 88)
Angle DFE = 90 degrees
Answer:
La arista de la bodega debe medir 6 metros.
Step-by-step explanation:
Podemos encontrar la arista de la bodega sabiendo su volumen:
En donde:
V: es el volumen de un cubo = 216 m³
a: es la arista del cubo =?
La arista del cubo es:
![a = \sqrt[3]{V} = \sqrt[3]{216 m^{3}} = 6 m](https://tex.z-dn.net/?f=%20a%20%3D%20%5Csqrt%5B3%5D%7BV%7D%20%3D%20%5Csqrt%5B3%5D%7B216%20m%5E%7B3%7D%7D%20%3D%206%20m%20)
Por lo tanto, la arista de la bodega debe medir 6 metros.
Espero que te sea de utilidad!
Answer:
a=±5
Step-by-step explanation:
25=5^2
Given that, x^2−10x+25=x^2−10x+5^2
Identity: a^2−2(ab)+b^2=(a-b)^2
Here, a=x and b=5
∴=(x−5)^2
Hope this helps
We can find the area of each shape separately
The area of the triangle can be found by A = 1/2bh
So the area will be 1/2 times (6+14+6= 26) 26 times 21
The area of the triangle will be 273 ft^2
The area of the square will be A=lxh
So the area will be 14 times 14
So the area of the square will be 196 ft ^2
We then add the area of both shapes together to get the total area
273 + 196 = 469 ft^2
Answer:
B
Step-by-step explanation:
