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umka21 [38]
3 years ago
7

Which of the following represents a function?

Mathematics
1 answer:
Karolina [17]3 years ago
6 0

Answer:

C

Step-by-step explanation:

Because you put the numbers over it and that makes a fraction. Easy:))

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-5 (p+2)=2 (2p-15)+p
Bess [88]
-5 (p+2)=2 (2p-15)+p 

-5p-10=4p-30+p

  \text{Expand} 

-5p-10=5p-30
 

-10=5p-30+5p
  \text{Add 5p to both sides} 

-10=10p-30

 

-10+30=10p
  \text{Add 30 to both sides} 

20=10p
 

\dfrac{20}{10}=p  \text{Divide both sides by 10} 

p=2  \text{Solution}
6 0
3 years ago
In the set of real numbers, the first number less than -3 is -4. <br><br> TrueFalse
hodyreva [135]
True because first is 0, -1, -2, -3, and then it is -4 I hope this helps please mark me as brainliest.
3 0
3 years ago
A lighthouse is located on a small island 2 km away from the nearest point P on a straight shoreline and its light makes four re
ddd [48]

Answer:

62.8 km per min

Step-by-step explanation:

Let the diagram of this situation is shown below,

In which \theta is the angle made by light to the straight line joining the lighthouse and P,

∵ Light makes 4 revolutions per minute.

Also, 1 revolution = 2\pi radians

So, the change in angle with respect to t ( time ),

\frac{d\theta}{dt}=8\pi\text{ radians per min}

Let x be the distance of beam from P,

\implies \tan \theta = \frac{x}{2}

Differentiating with respect to x,

\sec^2 \theta \frac{d\theta}{dt}=\frac{1}{2}\frac{dx}{dt}

(1+\tan^2 \theta) (8\pi) = \frac{1}{2}\frac{dx}{dt}

(1+\frac{x^2}{2^2})(8\pi) = \frac{1}{2}\frac{dx}{dt}

If x = 1 km,

(1+\frac{1}{4})8\pi =\frac{1}{2}\frac{dx}{dt}

\frac{5}{4}8\pi = \frac{1}{2}\frac{dx}{dt}

\implies \frac{dx}{dt}=\frac{80\pi}{4}= 20\pi\approx 62.8\text{ km per min}

Hence, the beam of light moving along the shoreline with the speed of 62.8 km per min

7 0
4 years ago
What does it mean by "completing the square" and how do u do it?
faust18 [17]
Completing the square goes back to pythagorean thm
but the way u do it, u want to find a value that enable u to take sqrt of both sides and solve
x^2-8x+3=0
x^2-8x=-3
we need (x-4)^2 so add 16
(x-4)^2=-3+16
(x-4)^2=13
x-4=sqrt13
x=4(+/-)sqrt13
4 0
4 years ago
Simplify: b3·b−5·b11<br> A) b9 <br> B) b15 <br> C) b19 <br> D) b-165
elena-14-01-66 [18.8K]
The answer should be C
(Hope this helps) :)
7 0
4 years ago
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