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Lady_Fox [76]
3 years ago
12

All of these sequences of transformations would return a shape to its original position except? a. Translate 3 units up, then 3

units down b. Reflect over line p, then reflect over line p again c. Translate 1 unit to the right, then 4 units to the left, then 3 units to the right. d.Rotate 120 degrees around center c then rotate 220 degrees around c again
Mathematics
1 answer:
zhenek [66]3 years ago
4 0

Answer:

Except d. Rotate 120 degrees around center c then rotate 220 degrees around again.

Step-by-step explanation:

Let's choose an arbitrary shape to work with the exercise.

For example a square (All the conclusions that we will make can be use with any shape).

For a. Translate 3 units up, then 3 units down is easy to see that this will return the square to its original position. Wherever we translate up and then down the same units a particularly shape this will return to its original position.

For b. Reflect over line p, then reflect over line p again

Wherever we have any particularly shape and we reflect over an arbitrary line twice, the shape will return to its original position. Particularly, the composition of two reflections over the same line is the identity function.

The identity function is the function that doesn't change the shape (It is the analogy of the multiplication by 1 with the common product between real numbers).

c. Translate 1 unit to the right, then 4 units to the left, then 3 units to the right.

The composition of this three translation will return the square to its original position (Same reasoning as a.)

d. Rotate 120 degrees around center c then rotate 220 degrees around c again.

Given that we choose an arbitrary center c and then chosen an arbitrary rotation sense (counterclockwise or clockwise), the composition of the two rotations is a 340 degrees rotation (given that we sum the degrees).

This transformation will not return a shape to its original position

(Of course, it exists some exceptions such as a rotation of a circle around its center. For any value of degrees, the rotation of a circle around its center will return the circle to its original position).

Generally, option d. is the correct option.

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Answer:

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7(4x+1)−3x=5x−13

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Subtract 5x from each side

25x-5x +7 = -13

20x +7 = -13

Subtract 7 from each side

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A parallelogram has a base of 4.5 cm and an area of 9.495 cm². Tania wrote the equation 4.5x = 9.495 to represent this situation
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Answer:

The height of the parallelogram is 2.11 cm.

Step-by-step explanation:

Area of the parallelogram is equal to multiplication of base and height.

Given:

Parallelogram has base of 4.5 cm.

Are of the parallelogram is 9.495 cm².

Equation is 4.5x=9.495

Calculation:

(a)

Are of the parallelogram is the product of base length and height of the parallelogram.

Area of the parallelogram is expressed as follow:

A=lh          

Substitute 9.495 cm² for A and 4.5 cm for l in above equation as follows:

9.495=4.5h             …… (1)

Now relate the equation (1) and given equation. So, here x is nothing but the height of the parallelogram.

(b)

From equation (1), height of the parallelogram is calculated as follows:

9.495=4.5h

h=\frac{9.495}{4.5}

h=2.11 cm

Thus, the height of the parallelogram is 2.11 cm.

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