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Lady_Fox [76]
3 years ago
12

All of these sequences of transformations would return a shape to its original position except? a. Translate 3 units up, then 3

units down b. Reflect over line p, then reflect over line p again c. Translate 1 unit to the right, then 4 units to the left, then 3 units to the right. d.Rotate 120 degrees around center c then rotate 220 degrees around c again
Mathematics
1 answer:
zhenek [66]3 years ago
4 0

Answer:

Except d. Rotate 120 degrees around center c then rotate 220 degrees around again.

Step-by-step explanation:

Let's choose an arbitrary shape to work with the exercise.

For example a square (All the conclusions that we will make can be use with any shape).

For a. Translate 3 units up, then 3 units down is easy to see that this will return the square to its original position. Wherever we translate up and then down the same units a particularly shape this will return to its original position.

For b. Reflect over line p, then reflect over line p again

Wherever we have any particularly shape and we reflect over an arbitrary line twice, the shape will return to its original position. Particularly, the composition of two reflections over the same line is the identity function.

The identity function is the function that doesn't change the shape (It is the analogy of the multiplication by 1 with the common product between real numbers).

c. Translate 1 unit to the right, then 4 units to the left, then 3 units to the right.

The composition of this three translation will return the square to its original position (Same reasoning as a.)

d. Rotate 120 degrees around center c then rotate 220 degrees around c again.

Given that we choose an arbitrary center c and then chosen an arbitrary rotation sense (counterclockwise or clockwise), the composition of the two rotations is a 340 degrees rotation (given that we sum the degrees).

This transformation will not return a shape to its original position

(Of course, it exists some exceptions such as a rotation of a circle around its center. For any value of degrees, the rotation of a circle around its center will return the circle to its original position).

Generally, option d. is the correct option.

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. How can you know if 2 shapes are congruent? Draw an example of 2 congruent triangles and label how you know.
ValentinkaMS [17]

Triangle ABC and triangle DEF are congruent by the SAS Congruence Postulate

<h3>What are congruent triangles?</h3>

Two triangles are said to be congruent if they have the same shape and their corresponding sides are also congruent.

We can say that two triangles are congruent using these 5 rules:

1: SSS or the side, side, side rule, that means that we have two triangles with all three sides equal.

2. SAS or side, angle, side states that in the two triangles, two sides and the included angle are equal.

3. ASA or angle, side, angle states that in two triangles, the two angles and the included side are equal.

4. AAS or angle, angle, side states that we have two triangles where two angles and the non-included side are equal.

5. HL or the Hypotenuse Leg rule states that, if the hypotenuse and one leg of one right-angled triangle are equal to the corresponding hypotenuse and leg of another right-angled triangle, then the two triangles are congruent.

Two triangles are said to be congruent if they have the same shape and their corresponding sides are also congruent.

Example:-From the diagram, given that:

AB = DE, BC = EF and ∠B = ∠E

Triangle ABC and triangle DEF are congruent by the SAS Congruence Postulate

Find out more on congruent triangles at:

brainly.com/question/2644832

#SPJ1

6 0
2 years ago
First,i would rewrite 3/4 as an equivalent fraction with a denominator of ____
Aleks04 [339]

Answer:

denominator of 12 (first blank) making the numerator 9. equivalent fraction 9/12 (second blank)

Step-by-step explanation:

lowest common denominator is 12. make sure what you do to the denominator (4times3)= 12, you do to the numerator (3times3)=9

8 0
3 years ago
What is the volume of the composite figure? Use 3.14 for π and round the answer to the nearest tenth of a cubic unit.
Bumek [7]
To find volume of a cylinder, you must find the area of the base and multiply it by the height of the object.

V=Bh where B=area of the base. Since the base is a circle, we must find area of the circle. A=pi(r^2)
A=3.14(6^2) Since it gave us the diameter, we take half for radius. Solve A=3.14(36)
A= 113.04 square cm

Now to find volume.
V=113.04•11
V=1243.44 cubic cm

Now find volume of the cone on top.

V=1/3Bh again with B= area of the base (pi)(r^2)
Since the two objects share a base, we can use the area of the cylinder as above.
V=1/3(113.04)9
We have to do a little simple math to determine the height of just the cone. Total height is 20-11 height of the cylinder. The difference is 9.
V=1/3(113.04)9 multiply
V=339.12 cubic cm

Now add the two volumes together to find total volume.
Total V=1243.44+339.12
V=1582.56 cubic cm
3 0
3 years ago
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8 0
3 years ago
Explain how 49. 567 is done in fraction form
pav-90 [236]
<span>= 49567/1000

</span>rite the decimal number as a fraction
(over 1)
49.567 = 49.567 / 1

Multiplying by 1 to eliminate 3 decimal places
we multiply top and bottom by 3 10's

Numerator (N)
N = 49.567 × 10 × 10 × 10 = 49567
Denominator (D)
D = 1 × 10 × 10 × 10 = 1000

N / D = 49567 / 1000

Simplifying our fraction

<span>= 49567/1000</span>
7 0
3 years ago
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