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Slav-nsk [51]
3 years ago
13

HEKP ASAP IM BEING TIMEDDDD!!!!!!

Mathematics
1 answer:
Aneli [31]3 years ago
3 0

Answer:

subtract 2.4 from both sides,  simplify to -3x=16.8, divide by -3, simplify to x=-5.6.

Step-by-step explanation:

-3x + 2.4 = 19.2

 v     <u>-2.4</u>   <u>-2.4</u>

 v       0      16.8

    <u>-3x</u>=<u>16.8</u>

     -3    -3

       x=-5.6

hope this helps,

<h3>Noelle</h3>
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Solve the system of equations y = 40x2 and y = 19x + 3 algebraically.
ikadub [295]

We have been given a system of nonlinear equations.

\\y=40x^{2},y=19x+3

In order to solve this system we can first equate the two equations in order to get a quadratic in x.

\\40x^{2}=19x+3

Our next step is to bring all the terms on one side.

\\40x^{2}-19x-3=0

Now we have to solve this equation. We can solve it by factoring using the splitting middle term method.

\\40x^{2}-24x+5x-3=0

\\8x(5x-3)+(5x-3)=0

\\(8x+1)(5x-3)=0

Upon setting each of these factors equal to zero using zero product property we get

\\8x+1=0 \text{ or } 5x-3 = 0

Upon solving both these equations we get

\\x=-\frac{1}{8} \text{ or } x=\frac{3}{5}

Now we can substitute these values of x in the equation

y=19x+3

We get

\text{For }x=- \frac{1}{8} \Rightarrow y=19(- \frac{1}{8})+3= \frac{5}{8}\\

\text{For }x= \frac{3}{5}\Rightarrow y=19( \frac{3}{5})+3= \frac{72}{5}\\

Therefore, our final set of solutions are

(x,y)=(- \frac{1}{8},\frac{5}{8}) \text{ and } ( \frac{3}{5}, \frac{72}{5})


6 0
3 years ago
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hjlf

Answer:

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Answer:

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