Y=4 pls brainliest me thanks
Let's begin by listing out the information given to us:
There are four students: n = 4
Number of students to be selected: r = 2
To calculate the combination of 2 students to be chosen, we use:
Therefore, there 12 possible combinations from these
If the angles are congruent then m∠ACB is 50°.
4x+4=6x-14
-4 -4
4= 2x-14
+14 +14
18=2x
x=9
Plug into one of the expressions.
4(9)+4
46+4
50
Sadly I do not know the scale factor rule yet. Just one lesson ahead :(
I hope I helped on first!
Answer:
C. 48 ways
Step-by-step explanation:
3 x 2 x 8 = 48 ways
Since all the angles are congruent, the sides must be congruent too.
So, just have one equation on one side equal to another.
5x= 3x+6
Subtract 3x from both sides.
2x=6
Divide 2 into both sides.
x=3.
We can check this by seeing if all the sides are the same.
5(3)= 15
6(3)-5= 15
3(3)+6= 15
I hope this helps!
~cupcake
