Step one calculate the moles of each element
that is moles= % composition/molar mass
molar mass of Ca = 40g/mol, S= 32 g/mol , O= 16 g/mol
moles of Ca = 29.4 /40g/mol=0.735 moles, S= 23.5/32 =0.734 moles, O= 47.1/16= 2.94 moles
calculate the mole ratio by dividing each mole with smallest mole that is 0.734
Ca= 0.735/0.734= 1, S= 0.734/0.734 =1, O = 2.94/ 0.734= 4
therefore the emipical formula = CaSO4
Answer:
i guess b is the answer.hope it will help
EM is created by moving charges back and forth will produce oscillating electric and magnetic fields, and these travel at the speed of light
<h3>
Answer:</h3>
2670 g Hg
<h3>General Formulas and Concepts:
</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>Explanation:
</h3>
<u>Step 1: Define</u>
8.02 × 10²⁴ atoms Hg
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of Hg - 200.59 g/mol
<u>Step 3: Convert</u>
- Set up:
![\displaystyle 8.02 \cdot 10^{24} \ atoms \ Hg(\frac{1 \ mol \ Hg}{6.022 \cdot 10^{23} \ atoms \ Hg})(\frac{200.59 \ g \ Hg}{1 \ mol \ Hg})](https://tex.z-dn.net/?f=%5Cdisplaystyle%208.02%20%5Ccdot%2010%5E%7B24%7D%20%5C%20atoms%20%5C%20Hg%28%5Cfrac%7B1%20%5C%20mol%20%5C%20Hg%7D%7B6.022%20%5Ccdot%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20Hg%7D%29%28%5Cfrac%7B200.59%20%5C%20g%20%5C%20Hg%7D%7B1%20%5C%20mol%20%5C%20Hg%7D%29)
- Divide/Multiply:
![\displaystyle 2671.42 \ g \ Hg](https://tex.z-dn.net/?f=%5Cdisplaystyle%202671.42%20%5C%20g%20%5C%20Hg)
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
2671.42 g Hg ≈ 2670 g Hg