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Sunny_sXe [5.5K]
3 years ago
11

Calculate the pH of a 5.99x10-2 M solution of HI

Chemistry
1 answer:
Anika [276]3 years ago
3 0

Answer:

Explanation:

pH = -log[H⁺] = -log(5.99 x 10⁻²) = 1.22 (3 sig. figs.)

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Iron is the very last product in stellar fusion is that; Iron has a tightly bound nucleus, and atoms larger than iron are less stable and tend to undergo nuclear fission.

The stability of an atom is dependent on the binding energy per nucleon of the atom.

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Beyond iron, we have exceeded the region of stable binding energy per nucleon of atoms. The atoms after iron in the curve are mostly unstable heavy nuclei.

Learn more: brainly.com/question/10095561

6 0
2 years ago
The barium isotope 133ba has a half-life of 10.5 years. a sample begins with 1.1×1010 133ba atoms. how many are left after (a) 5
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<span>a) 7.9x10^9 b) 1.5x10^9 c) 3.9x10^4 To determine what percentage of an isotope remains after a given length of time, you can use the formula p = 2^(-x) where p = percentage remaining x = number of half lives expired. The number of half lives expired is simply x = t/h where x = number of half lives expired t = time spent h = length of half life. So the overall formula becomes p = 2^(-t/h) And since we're starting with 1.1x10^10 atoms, we can simply multiply that by the percentage. So, the answers rounding to 2 significant figures are: a) 1.1x10^10 * 2^(-5/10.5) = 1.1x10^10 * 0.718873349 = 7.9x10^9 b) 1.1x10^10 * 2^(-30/10.5) = 1.1x10^10 * 0.138011189 = 1.5x10^9 c) 1.1x10^10 * 2^(-190/10.5) = 1.1x10^10 * 3.57101x10^-6 = 3.9x10^4</span>
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