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Sunny_sXe [5.5K]
3 years ago
11

Calculate the pH of a 5.99x10-2 M solution of HI

Chemistry
1 answer:
Anika [276]3 years ago
3 0

Answer:

Explanation:

pH = -log[H⁺] = -log(5.99 x 10⁻²) = 1.22 (3 sig. figs.)

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What is the ph of a 0.0055 m ha (weak acid) solution that is 8.2% ionized?
Trava [24]
Answer is: pH value of weak is 3.35.
Chemical reaction (dissociation): HA(aq) → H⁺(aq) + A⁻(aq).
c(HA) = 0.0055 M.
α = 8.2% ÷ 100% = 0.082.
[H⁺] = c(HA) · α.
[H⁺] = 0.0055 M · 0.082.
[H⁺] = 0.000451 M.
pH = -log[H⁺].
pH = -log(0.000451 M).
pH = 3.35.
pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity <span>an aqueous solution.</span>
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3 years ago
Suppose you put a whole antacid tablet in one glass of water and a crushed antacid tablet in another glass containing the same a
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The crushed tablets would stop bubbling/fuzzing first because it has a smaller surface area which means that it would dissolve before the uncrushed tablets which has a larger surface area.
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3 years ago
What must be true when work is done?
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7 0
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Where are the electrons found in Bohr's atomic model?
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Answer:

In the shell...

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How many particles are present in 10.0 moles of table salt?
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