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Norma-Jean [14]
3 years ago
9

An atom's nucleus has 92 protons and its mass number is 235. how many neutrons are in the nucleus? what is the name of the atom

Chemistry
1 answer:
STALIN [3.7K]3 years ago
6 0
The mass number is the sum of the protons and neutrons in an atom. 235-92 = 143 neutrons.
Element 92 is Uranium.

Uranium is also the highest atomic number element which exists in nature. All of the rest above element 92 only exist nuclear high-energy reactions (the transuranium elements), and most experience nuclear decay very quickly and form other elements with fewer protons. 
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Carla is working as a forensic investigator who specializes in specific time of death analysis. She is called into the lab to he
gregori [183]

Answer:

3 p.m most probably.

Explanation:

They found it at Monday 5 pm so its done before that time so its 3 p.m

8 0
2 years ago
2. From each of the following pairs of atoms, pick the atom that has
Zina [86]

Answer:

a) Na

c) Na

b) Sr

d) Ca

Explanation:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.

7 0
3 years ago
According to the following reaction, how many moles of chlorine gas are necessary to form 0.739 moles carbon tetrachloride? carb
Ilia_Sergeevich [38]

Answer:

2.956 moles chlorine gas will be produced

Explanation:

Step 1: data given

Number of moles carbon tetrachloride (CCl4) = 0.739 moles

carbon disulfide (s) = CS2(s)

chlorine (g) = Cl2(g)

carbon tetrachloride (l) = CCl4(l)

sulfur dichloride (s) = SCl2 (s)

Step 2: The balanced equation

CS2(s) + 4Cl2(g) → CCl4(l) +2SCl2

Step 3: Calculate moles chlorine gas

For 1 moles Cs2 we need 4 moles Cl2 to produce 1 mol CCl4 and 2 moles SCl2

For 0.739 moles CCl4 we need 4*0.739 = 2.956 moles Cl2

2.956 moles of chlorine gas will be produced

4 0
3 years ago
A force that acts on rock to change its shape or volume is called
sineoko [7]

Answer:

The answer would be stress

Explanation:

A force that acts on rock to change its shape or volume is stress. Stress adds energy to the rock. The energy is stored in the rock until it changes shape or breaks. Three different kinds of stress can occur in the crust—tension, compression, and shearing.

I hope this helps

8 0
3 years ago
The diameter of a biscuit is approximately 51 millimeters (mm). An atom of bismuth (Bi) is approximately 320. picometers (pm) in
astraxan [27]

Answer:

1.5e+8 atoms of Bismuth.

Explanation:

We need to calculate the <em>ratio</em> of the diameter of a biscuit respect to the diameter of the atom of bismuth (Bi):

\\ \frac{diameter\;biscuit}{diameter\;atom(Bi)}

For this, it is necessary to know the values in meters for any of these diameters:

\\ 1m = 10^{3}mm = 1e+3mm

\\ 1m = 10^{12}pm = 1e+12pm

Having all this information, we can proceed to calculate the diameters for the biscuit and the atom in meters.

<h3>Diameter of an atom of Bismuth(Bi) in meters</h3>

1 atom of Bismuth = 320pm in diameter.

\\ 320pm*\frac{1m}{10^{12}pm} = 3.20*10^{-10}m

<h3>Diameter of a biscuit in meters</h3>

\\ 51mm*\frac{1}{10^{3}mm} = 51*10^{-3}m = 5.1*10^{-2}m

<h3>Resulting Ratio</h3>

How many times is the diameter of an atom of Bismuth contained in the diameter of the biscuit? The answer is the ratio described above, that is, the ratio of the diameter of the biscuit respect to the diameter of the atom of Bismuth:

\\ Ratio_{\frac{biscuit}{atom}}= \frac{5.1*10^{-2}m}{3.20*10^{-10}m}

\\ Ratio_{\frac{biscuit}{atom}}= \frac{5.1}{3.20}\frac{10^{-2}}{10^{-10}}\frac{m}{m}

\\ Ratio_{\frac{biscuit}{atom}}= \frac{5.1}{3.20}\frac{10^{-2}}{10^{-10}}\frac{m}{m}

\\ Ratio_{\frac{biscuit}{atom}}= 1.5*10^{-2+10}

\\ Ratio_{\frac{biscuit}{atom}}= 1.5*10^{8}=1.5e+8

In other words, there are 1.5e+8 diameters of atoms of Bismuth in the diameter of the biscuit in question or simply, it is needed to put 1.5e+8 atoms of Bismuth to span the diameter of a biscuit in a line.

6 0
3 years ago
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