Ask question

Ask question

All categories

3 years ago

12

What’s the slope of the line?

1 answer:

notsponge [240]3 years ago

4 0

Answer:

Change in Y divided by change in X.

Step-by-step explanation

You might be interested in

If you have a 21oz cereal and the price is 2.94 what is the unit price

just olya [345]

For 21 Oz, price is 2.94
So, for 1 Oz, it would be: 2.94 / 21 = 0.14

In short, Your Answer would be $0.14 cereal per oz.

Hope this helps!

6 0

3 years ago

Read 2 more answers

Which equation is equivalent to 9x+4y=16

g100num [7]

Answer:

8x time 2x= 16

4 0

3 years ago

Last semester you took 3 final exams and you want to figure out which exam score really is your best score. Here are the scores

Mademuasel [1]

Answer:

76

Step-by-step explanation:

6 0

3 years ago

The Town of Hertfordshire clerk knows that 23% of dogs in the town have completed emotional support training. Hertfordshire plan

Nataly_w [17]

Answer:

95.64% probability that under 30% of the dogs are emotional support trained

Step-by-step explanation:

For each dog, there are only two possible outcomes. Either they have completed emotional support training, or they have not. So we use the binomial probability distribution to solve this problem.

However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$\mu = E(X) = np = 100*0.23 = 23$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.23*0.77} = 4.21$

What is the probability that under 30% of the dogs are emotional support trained?

30% of 100 is 0.3*100 = 30

So this is the pvalue of Z when X = 30.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{30 - 23}{4.1}$

$Z = 1.71$

$Z = 1.71$ has a pvalue of 0.9564.

So there is a 95.64% probability that under 30% of the dogs are emotional support trained

5 0

3 years ago

Assume that the weight of two year old babies have distribution that is approximately normal with a mean of 29 pounds and a stan

Lana71 [14]

Answer:

25.15 ponds is the weight of two year old baby corresponds to 10th percentile.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 29 pounds

Standard Deviation, σ = 3 pounds

We are given that the distribution of weight of two year old babies is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.10

P(X < x)

$P( X < x) = P( z < \displaystyle\frac{x - 29}{3})=0.10$

Calculation the value from standard normal z table, we have,

$P(z < -1.282) = 0.10$

$\displaystyle\dfrac{x - 29}{3} = -1.282\\x = 25.154 \approx 25.15$

Thus, 25.15 ponds is the weight of two year old baby corresponds to 10th percentile.

5 0

3 years ago