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ArbitrLikvidat [17]
3 years ago
5

How large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius

110 m at a speed of 101 km/h
Physics
1 answer:
mixas84 [53]3 years ago
6 0

The magnitude of static friction is

<em>f</em> = <em>mv</em> ²/<em>r</em>

(i.e. the net force acting on the car parallel to the road points toward the center of the curve)

while the net vertical force must be

∑ <em>F</em> = <em>n</em> - <em>mg</em> = 0

because the car is otherwise in equilibrium. Then

==>   <em>n</em> = <em>mg</em>

==>   <em>f</em> = <em>µn</em> = <em>µmg</em> = <em>mv</em> ²/<em>r</em>

==>   <em>µ</em> = <em>v</em> ²/(<em>rg</em>)

We have

<em>v</em> = 101 km/h ≈ 28.1 m/s

<em>r</em> = 110 m

<em>g</em> = 9.80 m/s²

so that

<em>µ</em> = (28.1 m/s)² / ((110 m) <em>g</em>) ≈ 0.730

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mixas84 [53]
The answer would be C. 5m
This is because to find d, you would need to divide W (125 J) by F (25 N).
Hope this helps!
8 0
3 years ago
A girl of mass 50.6 kg stands on the edge of a frictionless merry-go-round of mass 827 kg and radius 3.72 m that is not moving.
GaryK [48]

Answer:

(a). The value of angular speed of the merry-go-round \omega = - 5.82 × 10^{-3} \frac{rad}{s}

(b). The linear speed of the girl after the rock is thrown V = -1.89 × 10^{-2} \frac{m}{s}

Explanation:

Given data

Mass of the girl m_{g} = 50.6 kg

Mass of merry-go-round m_{m} = 827 kg

Radius r = 3.72 m

The speed of the rock relative to the ground V_{r} = 7.82 \frac{m}{s}

(a). The angular speed of the merry-go-round is given by

\omega = - [\frac{m_{r}v_{r}  }{r} ] \frac{2}{m_{m} + 2m_{g} }

Put all the values in above formula

\omega = \frac{(1.13)(7.82)}{3.27} \frac{2}{827 + (2)50.6}

\omega = - 5.82 × 10^{-3} \frac{rad}{s}

This is the value of angular speed of the merry-go-round.

(b). The liner speed of the girl is given by

⇒ V = r × \omega

⇒ V = - 3.72 × 5.82 × 10^{-3}

⇒ V = -1.89 × 10^{-2} \frac{m}{s}

This is the linear speed of the girl after the rock is thrown.

7 0
3 years ago
Which solution will have more gas dissolved in it, A solution under high-pressure or one under low pressure?
gayaneshka [121]
High pressure, because the more pressure, the less volume, so the atoms have to get closer together.
4 0
3 years ago
What must a magnet always have?
Rainbow [258]

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two opposite poles

Explanation:

3 0
3 years ago
Read 2 more answers
A car (mass 5 1100 kg) is traveling at 32 m/s when it collides headon with a sport utility vehicle (mass 5 2500 kg) traveling in
Elan Coil [88]

Answer:

speed was the sport utility vehicle traveling is 14.08 m/s

Explanation:

Given data

car mass m1 = 1100 kg

speed s = 32 m/s

vehicle mass m2 = 2500 kg

to find out

speed was the sport utility vehicle traveling

solution

we will apply here conservation of momentum law

the momentum change of car  is equal  and opposite of the momentum change of vehicle

so equation are

m1 v1 - m2 v2 = 0

so here v2 will be

v2 = (m1 / m2 ) v1

put here all these value we get

v2 = (1100 /  2500 ) 32

v2 =  14.08 m/s

so speed was the sport utility vehicle traveling is 14.08 m/s

8 0
3 years ago
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