The answer would be C. 5m
This is because to find d, you would need to divide W (125 J) by F (25 N).
Hope this helps!
Answer:
(a). The value of angular speed of the merry-go-round
= - 5.82 ×

(b). The linear speed of the girl after the rock is thrown V = -1.89 ×

Explanation:
Given data
Mass of the girl
= 50.6 kg
Mass of merry-go-round
= 827 kg
Radius r = 3.72 m
The speed of the rock relative to the ground
= 7.82 
(a). The angular speed of the merry-go-round is given by
![\omega = - [\frac{m_{r}v_{r} }{r} ] \frac{2}{m_{m} + 2m_{g} }](https://tex.z-dn.net/?f=%5Comega%20%3D%20-%20%5B%5Cfrac%7Bm_%7Br%7Dv_%7Br%7D%20%20%7D%7Br%7D%20%5D%20%5Cfrac%7B2%7D%7Bm_%7Bm%7D%20%2B%202m_%7Bg%7D%20%7D)
Put all the values in above formula

= - 5.82 ×

This is the value of angular speed of the merry-go-round.
(b). The liner speed of the girl is given by
⇒ V = r × 
⇒ V = - 3.72 × 5.82 × 
⇒ V = -1.89 ×

This is the linear speed of the girl after the rock is thrown.
High pressure, because the more pressure, the less volume, so the atoms have to get closer together.
Answer:
speed was the sport utility vehicle traveling is 14.08 m/s
Explanation:
Given data
car mass m1 = 1100 kg
speed s = 32 m/s
vehicle mass m2 = 2500 kg
to find out
speed was the sport utility vehicle traveling
solution
we will apply here conservation of momentum law
the momentum change of car is equal and opposite of the momentum change of vehicle
so equation are
m1 v1 - m2 v2 = 0
so here v2 will be
v2 = (m1 / m2 ) v1
put here all these value we get
v2 = (1100 / 2500 ) 32
v2 = 14.08 m/s
so speed was the sport utility vehicle traveling is 14.08 m/s