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wlad13 [49]
3 years ago
8

A pear hangs in a tree at a height of 1.8 m. The pear has a mass of 0.2 kg. The pear falls out of the tree and lands on the grou

nd. (Use correct units in all answers.)
a. How much gravitational potential energy does the pear have before it falls?

b. How much kinetic energy does the pear have when it reaches the ground?

c. How fast is the pear moving when it hits the ground?
Physics
1 answer:
TiliK225 [7]3 years ago
6 0

a) PE=mgh=0.2*9.8*1.2=2.352 J

b) KE=PE=2.352 J

c) v=\sqrt{\frac{2KE}{m}}=4.85 m/s

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If runner A is running at 7.50 m/s and runner B is running at 7.90 m/s, how long will it take runner B to catch runner A if runn
yaroslaw [1]

Answer:

t= 137.5 s

Explanation:

So if we are wanting to figure out how long it takes runner B to catch runner A. we must first set the slope of each runner equal to one another

<u>Slopes:</u>

Runner A:    y = 7.50x + 55

Runner B:    y = 7.90 x

sooooo

  7.50 x + 55 = 7.90 x

- 7.50 x          - 7.50 x

 55 = .40 x

55/.40 = .40 x / .40

x = 137.5 s

t= 137.5 s

7.50 * 137.5 + 55 =1086.25 m

7.90 * 137.5 =  1086.25 m

3 0
2 years ago
21. Compare and contrast beta particles to the electrons that surround neutral atoms.
stiv31 [10]
Beta particles come from the nucleus. Electrons are found around the nucleus.
Beta particles normally travel very fast out of a nucleus in a straight line. Electrons normally orbit the nucleus of an atom.

They both have the same mass and the same charge.
6 0
3 years ago
Which waves are longitudinal waves? Check all that apply.
alekssr [168]
Sound waves.
Eathquake P-Waves
7 0
3 years ago
Read 2 more answers
A parcel of air at 5 km. and an initial temperature of 10°C altitude descends to 3 km altitude at the unsaturated adiabatic laps
Alchen [17]

Answer:

30 degrees Celsius

Explanation:

With unsaturated adiabatic lapse rate water vapour does not have to change state from gaseous to liquid.

7 0
3 years ago
The New England Merchants Bank Building in Boston is 152 m high. On windy days it sways with a frequency of 0.17 Hz, and the acc
aksik [14]

Answer:

d = 8.4 cm

Explanation:

In order to calculate the amplitude of oscillation of the top of the building, you use the following formula for the max acceleration of as simple harmonic motion:

a_{max}=A\omega^2           (1)

A: amplitude of the oscillation

w: angular speed of the oscillation = 2\pif

f: frequency = 0.17Hz

The maximum acceleration of the top of the building is a 2.0% of the free-fall acceleration. Then, you have:

a_{max}=0.02(9.8m/s^2)=0.196\frac{m}{s^2}

Then, you solve for A in the equation (1) and replace the values of the parameters:

A=\frac{a_{max}}{\omega^2}=\frac{a_{max}}{4\p^2i f^2}\\\\A=\frac{0.196m/s^2}{16\pi^2(0.17Hz)^2}\\\\A=0.042m=4.2cm

The total distance, side to side, of the oscilation of the top of the building is twice the amplitude A. Then you obtain:

d = 2A = 2(4.2cm) = 8.4cm

4 0
3 years ago
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