Answer:
tan(x-y) = -16/63
Step-by-step explanation
Tan(x-y) if cscx=13/5 and coty=4/3
Given
coty = 4
1/tany = 4/3
Cross multiply
tan y = 3/4
Also since cscx = 13/5
1/sinx = 13/5
sinx = 5/13
Since sinx = opp/hyp
opp = 5
hyp = 13
Get the adjacent
hyp² = opp²+adj²
13² = 5²+adj²
adj² = 13² - 5²
adj² = 169 - 25
adj² = 144
adj = 12
cosx = adj/hyp
cosx = 12/13
tanx = sinx/cosx
tanx = (5/13)/(12/13)
tanx = 5/13 * 13/12
tan x = 5/12
tan(x-y) = tanx - tany/1+tanxtany
tan(x-y) = (5/12 - 3/4)/1+(5/12)(3/4)
tan(x-y) = (5-9/12)/1+5/16
tan(x-y) = -4/12/(21/16)
tan(x-y) = -1/3 * 16/21
tan(x-y) = -16/63
Steps To Solve:
-5(3 * -7 + 4y)
~Solve what's in parenthesis
-5(-21 + 4y)
~Distributive Property
105 - 20y
Hope This Helped! Good Luck!
Answer:
is linearly dependent set.
Step-by-step explanation:
Given: 
is a linearly dependent set in set of real numbers R
To show: the set is linearly dependent.
Solution:
If 
is a set of linearly dependent vectors then there exists atleast one 
such that 
Consider 
A linear transformation T: U→V satisfies the following properties:
1. 
2. 
Here, 
∈ U
As T is a linear transformation,
As is a linearly dependent set,
for some 
So, for some
Therefore, set is linearly dependent.
Well, i would use the distance formula to find the distance between the two points. Only issue- you do not have the other point, so lets find it!
We have the point 4,6. 4 is the x, and 6 is the y.
Lets start with 4 since the x works with the left and right aspect of the location. It says M has been translated 8 units to the left, meaning we go back 8. So if we are at 4, and we go back (A.K.A. Subtract) 8, we will be at -4.
Now lets move onto the y, which works with the up and down aspect of the location. It says M has been translated 9 unites down, meaning the point will be heading down and getting smaller. So if we are at 6, and we go down (A.K.A. subtract) 9, then we will be at -3.
So now we have the coordinates of point M (4,6) and point M' (-4,-3) so we can now complete the distance formula!
The distance formula helps determine the distance between two points. It looks like this: D = √(x₂-x₁)²+(y₂-y₁)²
Though it does not matter which order you use the coordinates in, i am choosing to use M and then M'.
So, starting with the X, X₂ will be -4 and X₁ will be 4.
Again, starting with the Y, Y₂ will be -3 and Y₁ will be 6.
So, the formula plugged in will look like this: d = √(-4 - 4)² + (-3 - 6)²
Solving it out, we first need to work within the parenthesis. Can you solve it?
Our outcome will be this: -8² + -9². But, since we are squaring (And a negative times a negative equals a positive) you can just write 8² + 9²
8²= 64
9²= 81
64+81 = 145.
So, the distance between point M and point M' would be 145 units
Hope this helps!
If it does not, please let me know so i can try to help!
Answer:
2550yards
Step-by-step explanation:
Perimeter of a rectangle = 2L + 2W
L is the length
W is the width
If perimeter of a rectangle is 425 yards, then;
425 = 2L + 2W
425 = 2(L+W)
L+W = 425/2 .... 1
If the length and width of the rectangle are each multiplied by 6
P = 6(2L) + 2(2W)
P = 12L + 12W
P = 12(L+W) .... 2
Substitute 1 into 2
P = 12(425/2)
P = 6*425
P = 2550yd
Hence the perimeter of new triangle is 2550yards
