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kap26 [50]
3 years ago
11

A store is having a sale to celebrate President's Day. Every item in the store is advertised as 1/5 off the original price. If a

n item is marked with a sale price of $140, what was its original price? Show your work
Mathematics
1 answer:
fomenos3 years ago
6 0
So 140=origonal price-1/5 so
represent origonal price with p
140=4/5p
multiply both sides by 5/4
175=p
the answer is 175
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9.67 x 10^-3 = 0.00967

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Question Help
ValentinkaMS [17]

Step-by-step explanation:

We assume that the advertising rates in this journal for full-page ads is x ($/ad); the rate for half-page ads is y ($/ad).

The revenue for 3 full page ads are: 3x ($)

The revenue for 5 half page ads are: 5y ($)

One issue of a journal has 3 full-page ads and 5 half-page ads, generating $6340.

=> The total revenue for 3 full page and 5 half page ads are $6340

=> 3x + 5y = 6340

The revenue for 4 full page ads are: 4x ($)

The revenue for 4 half page ads are: 4y ($)

One issue of a journal has 4 full-page ads and 4 half-page ads, generating $6625.

=> The total revenue for 4 full page and 4 half page ads are $6625

=> 4x + 4y = 6625 (1)

We have:

+) 3x + 5y = 6340

=> 5y = 6340 - 3x

=> y = (6340 - 3x)/5 = 1268 - 0.6x

Replace <em>y = 1268 - 0.6x </em>into (1), we have:

4x + 4y = 6625

⇔4x + 4(1268 - 0.6x) = 6625

⇔ 4x + 5072 - 2.4x = 6625

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=> y = 1268 - 0.6x = 1268 - 0.6*970.625= 1268 - 582.375 = 685.625

So the advertising rate for full page ads is $970.625, for half-page ads is $685.625

7 0
4 years ago
Write 50,722 in expanded form​
avanturin [10]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Write the equation for the parabola that has x− intercepts (−2,0) and (1.2,0) and y− intercept (0,−4).
schepotkina [342]

Answer: The answer is 15y+4=25(x-1.6)^2.


Step-by-step explanation:  We are to find the equation of the parabola with x-intercepts (-2,0), (1.2,0) and y-intercept (0,-4).

Therefore, axis of symmetry is

x=\dfrac{1.2+2}{2}\\\\\Rightarrow x=1.6.

Let the equation of the parabola be y=a(x-1.6)^2+k.

Substituting the points (x,y)=(0,-4) and (1.2,0) in the above equation, we find that

-4=a(0-1.6)^2+k\\\\\Rightarrow k=-2.56a-4

and

0=a(1.2-1.6)^2+k\\\\\Rightarrow k=-0.16a.

Solving the above two equations, we get

a=-\dfrac{5}{3}~~\textup{and}~~k=-\dfrac{4}{15}.

So, putting the values of 'a' and 'k' in the equation of the parabola, we get

y=-\dfrac{5}{3}(x-1.6)^2-\dfrac{4}{15}\\\\\Rightarrow 15y+4=-25(x-1.6)^2.

Thus, the equation of the parabola is  15y+4=25(x-1.6)^2.


3 0
4 years ago
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