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vesna_86 [32]
3 years ago
8

Which of the following statements is correct about ?

Mathematics
2 answers:
aliina [53]3 years ago
6 0
B is the best answer
Nookie1986 [14]3 years ago
5 0
 b is an <span> irrational number between 9 and 10</span>
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PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS
Elina [12.6K]

You want to end up with A\sin(\omega t+\phi). Expand this using the angle sum identity for sine:

A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi

We want this to line up with 2\sin(4\pi t)+5\cos(4\pi t). Right away, we know \omega=4\pi.

We also need to have

\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}

Recall that \sin^2x+\cos^2x=1 for all x; this means

(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}

Then

\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)

So we end up with

2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)

8 0
3 years ago
Read 2 more answers
Can someone help me answer these questions
babymother [125]
12. I’m sorry I’m horrible at word problems
13. C
14. C
3 0
2 years ago
Simplify the product using foil (6x-5)(2x-3)
telo118 [61]
FOIL
First = 6x(2x) = 12x
Outside = 6x(-3) = -18x
Inside = -5(2x) = -10x
Last = -5(-3) = 15
12x - 18x - 10x + 15
12x - 28 + 15
-16x + 15

Hope this helps =)
3 0
3 years ago
Read 2 more answers
5-5+x*7=14<br><br> What is x=
Novosadov [1.4K]
0+x*7=14
X=2 is the correct answer
8 0
3 years ago
Samantha must include 1 English class, 1 Algebra class, and 1 Biology class in a schedule. There 3 English teachers, 4 Algebra t
astra-53 [7]

To solve this problem, we make use of the formula of combination.

nCr = n! / r! (n – r)!

where n is the total number of subject teachers and r is the number of subjects r = 1

 

For the English class n = 3

3C1 = 3! / 1! (3 – 1)! = 3

 

For the Algebra class n = 4

4C1 = 4! / 1! (4 – 1)! = 4

 

 

For the Biology class n = 2

2C1 = 2! / 1! (2 – 1)! = 2

 

The total number of different schedules would be the product of the three combinations:

total combinations possible = 3 * 4 * 2

total combinations possible = 24

4 0
3 years ago
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