The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
Read more about vertex at:
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So lets say u have 100$ and it decreases by 100% u would have no money left
The number is 21 because 2 is 1 doubled, and 2+1 is 3.
Answer: B. neither
<u>Step-by-step explanation:</u>
A function is even when f(x) = f(-x).
A function is odd when f(-x) = -f(x).
f(x) = 2x³ - x²
f(-x) = 2(-x)³ - (-x)²
= -2x³ - x²
f(x) = 2x³ - x² ≠ f(-x) = -2x³ - x² so it is NOT EVEN
-f(x) = -(2x³ - x²)
= -2x³ + x²
f(-x) = -2x³ - x² ≠ -f(x)= -2x³ + x² so it is NOT ODD
Therefore, it is NEITHER even nor odd.
