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photoshop1234 [79]
2 years ago
7

Which operation will solve the following word problem? Jeff earns $14.00 per hour, Tom earns half as much as Jeff. How much does

Tom earn per hour?
Multiplication


Subtraction


Addition


Division
Mathematics
1 answer:
disa [49]2 years ago
5 0

Answer:

The correct option is (d).

Step-by-step explanation:

Given that,

Jeff earns $14.00 per hour.

Tom earns half as much as Jeff.

We need to find the amount earn by Tom per hour.

Tom's amount = Jeff's amount/2

So,

T=\dfrac{14}{2}\\\\T=\$7

So, Tom earn $7 per hour. Hence, division operation is used. Jeff's amount is divided by 2.

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Express the perimeter of one side of the square using s
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s is the length and w is width which the equation is  2s+2w=P

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3 years ago
Express 45 minutes as a fraction of 1 hour ​
Pepsi [2]

Answer:

\frac{3}{4}

Step-by-step explanation:

There are 60 minutes in 1 hour

To express as a fraction

\frac{45}{60}

Divide numerator/denominator by 15

\frac{45}{60} = \frac{3}{4}

8 0
3 years ago
Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3
Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

\frac{dV}{dt} = -kA

Using Euler's method

\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i}    \\

Where initial droplet volume is:

V(0) = \frac{4pi}{3} * r(0)^3 =  \frac{4pi}{3} * 2.5^3 = 65.45 mm^3

Hence, the iterative solution will be as next:

  • i = 1, ti = 0, Vi = 65.45

V'_{i}  = -k *4pi*(\frac{3*65.45}{4pi})^(2/3)  = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88

  • i = 2, ti = 0.5, Vi = 63.88

V'_{i}  = -k *4pi*(\frac{3*63.88}{4pi})^(2/3)  = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33

  • i = 3, ti = 1, Vi = 62.33

V'_{i}  = -k *4pi*(\frac{3*62.33}{4pi})^(2/3)  = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\

The average change of droplet radius with time is:

Δr/Δt = \frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

5 0
3 years ago
Write the following fractions greater than 1as a sum of two products
cestrela7 [59]
What are the following fractions
7 0
3 years ago
Variable y varies directly with variable x, and y = 5 when x = 8.
qaws [65]
Y = kx

Plug in what we know:

5 = k(8)

5 = 8k

Divide 8 to both sides:

k = 0.625

Plug this back into the equation along with y = 15:

y = kx

15 = 0.625x

Divide 0.625 to both sides:

x = 24
4 0
3 years ago
Read 2 more answers
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