Step-by-step explanation:
The awnser is -6+6 because it would end up being 0, which is not positive nor negative
Some information is missing for #6.
#7: use sine, sin35=h/5.1, h=5.1*sin35, use a calculator, h≈2.9
#23: to find the reference angle, keep subtracting the number by 360, until the remaining difference is the smallest positive number.
1406-360-360-360=326. the reference angle is 326.
now look at the remainder, the terminal line of 326 degree is in the 4th quadrant between 270 and 360, the the reference angle is 360-326=34, the angle between the terminal line and the positive x axis. 34 is the answer.
There are a number of ways this can be done. One that is fairly simple is as follows.
Triangle ABC has base AC = 9 and height B to AC of 3 (found by counting squares). Thus its area is ∆ABC = (1/2)·9·3 = 13.5 square units.
Triangle ACF has base AC = 9 and height F to AC of 3, so will have the same area as triangle ABC, 13.5 square units.
Trapezoid CDEF has base CD of 6, base EF of 4 and height EF to CD of 6 (found by counting squares). Thus its area is CDEF = (1/2)(6 + 4)(6) = 30.
The total area of the entire figure is then
... ∆ABC + ∆ACF + CDEF = 13.5 + 13.5 + 30 = 57 square units.
Answer:
hey
Step-by-step explanation:
diagonal PQ = root over l²+b²+h²
= root over 9+16+144
root over 169
=13 is your answer
Problem 1: -5^2 + 10^2
Work:
-5^2 + 10^2—> (-5 x -5) + (10 x 10) —> 25 + 100 = 125
Answer:
125
Problem 2: (2 x (-5) x 3) + 3^3
Work:
(2 x (-5) x 3) + 3^3 > (-25 x 3) + 3^3 —> -75 + 3^3 —> -75 + 27 —> 48
Answer:
48
