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Alexus [3.1K]
3 years ago
14

A car of mass 150 kg is riding down at constant velocity. What is the normal force?

Physics
2 answers:
Vladimir [108]3 years ago
8 0

Answer:

864N

Explanation:

xz_007 [3.2K]3 years ago
4 0

Answer:

1500N

Explanation:

Normal force = mg - F sin theta

constant velocity means acceleration = 0

F= ma = 150× 0 = 0N

thus;

normal force = mg = 150 × 10 = 1500N

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White blood cells are most closely associated with which two body’s systems
Vlad1618 [11]

Answer:

Explanation:

circulatory and digestive. ... An immune response is primarily due to the body's white blood cells recognizing.

8 0
2 years ago
Two coils have the same number of circular turns and carry the same current. Each rotates in a magnetic field acting perpendicul
Delicious77 [7]

Answer:

The radius of coil 2 = 2.7 cm

Explanation:

The number of coils = 2

It is given that both carry equal current and rotates in the magnetic field.

The given radius of coil 1 = 4.0 cm

Coil 1 rotates = 0.21 T field

Coil 2 rotates = 0.45 T filed.

The radius of coil 2 need to be calculated.

Torque action on dipole is given byT =NIABsinθ

here T1 = T2

r1^{2} \times  B1 = r2^{2} \times B2 \\r2^{2} = 0.04 \times 0.04 \times \frac{0.21}{0.45} \\r2 = 0.027m   \ or \ 2.7 cm \\

5 0
3 years ago
The velocity of the transverse waves produced by an earthquake is 8.9 km/s, and that of the longitudinal waves is 5.1 km/s. A se
Brrunno [24]

Answer: The distance is 723.4km

Explanation:

The velocity of the transverse waves is 8.9km/s

The velocity of the longitudinal wave is 5.1 km/s

The transverse one reaches 68 seconds before the longitudinal.

if the distance is X, we know that:

X/(9.8km/s) = T1

X/(5.1km/s) = T2

T2 = T1 + 68s

Where T1 and T2 are the time that each wave needs to reach the sesmograph.

We replace the third equation into the second and get:

X/(9.8km/s) = T1

X/(5.1km/s) = T1 + 68s

Now, we can replace T1 from the first equation into the second one:

X/(5.1km/s) = X/(9.8km/s) + 68s

Now we can solve it for X and find the distance.

X/(5.1km/s) - X/(9.8km/s) = 68s

X(1/(5.1km/s) - 1/(9.8km/s)) = X*0.094s/km= 68s

X = 68s/0.094s/km = 723.4 km

6 0
3 years ago
Which best summarizes a concept related to the work-energy theorem?
Maurinko [17]

Answer:

When work is positive, the environment does work on an object.

Explanation:

According to the work-energy theorem, the net work done by the forces on a body or an object is equal to the change produced in the kinetic energy of the body or an object.

The concept that summarizes a concept related to the work-energy theorem is that ''When work is positive, the environment does work on an object.''

4 0
3 years ago
Calcular la aceleración que produce una fuerza de 40 N sobre un cuerpo con 88 Kg de masa. Expresar el resultado en m⁄s^2 *
tigry1 [53]

Answer:

a = 0.45 m/s²

Explanation:

The given question is ''Calculate the acceleration that produces a force of 40 N on a body with 88 kg of mass".

Given that,

Force, F = 40 N

Mass of the body, m = 88 kg

The net force acting on the body is given by :

F = ma

Where

a is the acceleration of the body

a=\dfrac{F}{m}\\\\a=\dfrac{40\ N}{88\ kg}\\\\a=0.45\ m/s^2

So, the required acceleration is 0.45 m/s².

4 0
3 years ago
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