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1 year ago

Wolfgang pauli hypothesized an exclusion principle. This principle says two electrons in an atom cannot have the same what?.

1 answer:

3 0

No two electrons in an atom or molecule may have the same four electronic quantum numbers, according to the Pauli Exclusion Principle. Only two electrons can fit into an orbital at a time, hence they must have opposing spins.

<h3>What is Pauli's exclusion principle ?</h3>

According to Pauli's exclusion principle, two electrons cannot share the same orbital and must have anti-parallel or opposite spins. Example: Two bonded electrons in a neutral helium atom achieve the opposite spin to occupy the lowest-energy () states.

It is known as the exclusion principle because, in accordance with it, all other electrons in an atom are excluded from having the same set of specific values for the four quantum numbers as one electron in the atom.

Learn more about Pauli's exclusion principle here:

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3 years ago

A 0.750 kg block is attached to a spring with spring constant 17.5 N/m. While the block is sitting at rest, a student hits it wi

Dmitriy789 [7]

Answer:

$A = 0.081 \ m$

The value is $u = 0.2569 \ m/s$

Explanation:

From the question we are told that

The mass is $m = 0.750 \ kg$

The spring constant is $k = 17.5 \ N/m$

The instantaneous speed is $v = 39.0 \ cm/s= 0.39 \ m/s$

The position consider is x = 0.750A meters from equilibrium point

Generally from the law of energy conservation we have that

The kinetic energy induced by the hammer = The energy stored in the spring

$\frac{1}{2} * m * v^2 = \frac{1}{2} * k * A^2$

Here a is the amplitude of the subsequent oscillations

=> $A = \sqrt{\frac{m * v^ 2 }{ k} }$

=> $A = \sqrt{\frac{0.750 * 0.39 ^ 2 }{17.5} }$

=> $A = 0.081 \ m$

Generally from the law of energy conservation we have that

The kinetic energy by the hammer = The energy stored in the spring at the point considered + The kinetic energy at the considered point

$\frac{1}{2} * m * v^2 = \frac{1}{2} * k x^2 + \frac{1}{2} * m * u^2$

=> $\frac{1}{2} * 0.750 * 0.39^2 = \frac{1}{2} * 17.5* 0.750(0.081 )^2 + \frac{1}{2} * 0.750 * u^2$

=> $u = 0.2569 \ m/s$

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3 years ago

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3 years ago

In a thunder and lightning storm there is a rule of thumb that many people follow. After seeing the lightning, count seconds to

lubasha [3.4K]

Answer:

2.837% less than actual value.

Explanation:

Based on given information let's calculate our value.

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1mile = 1609.34meters.

percentage error is.

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