
Since the flower pot is dropped, it has an initial velocity of zero. Also the flower pot accelerates due to gravity.
so
Answer:
T = 540 N (to two significant digits)
Explanation:
Let the crate dimension L be from strap attachment to floor contact
Let T be the strap tension
sum moments about the floor contact point to zero
mg[½Lcos25] - Tsin61[Lcos25] + Tcos61[Lsin25] = 0
L is common to all terms, so divides out.
½(71)(9.8)cos25 = T(sin61cos25 - cos61sin25)
T = (71)(9.8)cos25 / (2(sin61cos25 - cos61sin25))
T = 536.428020...
5lbs is greater.
Hope that helps!
Throw it sideways and try to make it spin around but it needs to be thrown high up then it should kinda glide down