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juin [17]
4 years ago
14

??? True or false. An element can only exist as an individual atom.

Physics
1 answer:
KengaRu [80]4 years ago
7 0
I think it's false because Oxygen is diatomic so it's found as O2 which means that it has two atoms of itself.
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a vector points -43.0 units along the x-axis, and 11.1 units along the y-axis. find the magnitude of the vector
Sauron [17]

Answer:

the magnitude of the vector is 44,40 units

Explanation:

Using the Pythagoras theorem

M=\sqrt{(-43^{2} )+(11.1)^{2} } \\\\M= 44,4 units

3 0
3 years ago
Layla shot a balloon straight up in the air and it is in the air round trip for 6.80 s.
Katena32 [7]

Answer:

24mph

Explanation:

it really depends how high but the average speed for that quick will be atleast 24mph if not try 42mph if it is wrong

5 0
3 years ago
Consider the two-body system at the right. A 22.7-N block is placed upon an inclined plane which is inclined at a 17.2 degree an
artcher [175]

Answer:

Given that

For A weight Wt= 22.7 N

m₁ = 22.7/10 = 2.27 kg

Force alone inclined plane

Wt₁ = m₁ g sin θ

Wt₁  =22.7 sin 17.2°

Wt₁ = 6.7 N

For B weight Wt₂= 34.5-N

m₂ = 3.45 kg

coefficient of friction ,μ= 0.219

θ = 17.2 degree

The friction force on the block A

Fr= μ m₁ g cos θ

Fr= 0.216 x 22.7 x cos 17.2°

Fr= 4.68 N

Lets take acceleration of system is a m/s²

Tension = T

From Newtons law

Wt₂ - Wt₁ - Fr = (m₁ +m₂) a

34.5 -  6.7 - 4.68 = (2.27 + 3.45 ) a

a= 4.05 m/s²

Block B

Wt₂ - T = m₂ a

T = 34.5 - 4.05 x 3.45

T= 20.52 N

3 0
3 years ago
Question 2:
Vesna [10]

Explanation:

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So there are a wats up group where you can get help step by step and well explained by the trusted experts.

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3 0
3 years ago
Read 2 more answers
What is the de Broglie wavelength of an electron that strikes the back of the face of a TV screen at 1/10 the speed of light? __
Softa [21]

Answer: 2.42(10)^{-11} m

Explanation:

The de Broglie wavelength \lambda is given by the following formula:

\lambda=\frac{h}{p}   (1)

Where:

h=6.626(10)^{-34}\frac{m^{2}kg}{s} is the Planck constant

p is the momentum of the atom, which is given by:

p=m_{e}v_{e}   (2)

Where:

m_{e}=9.11(10)^{-31}kg is the mass of the electron

v=\frac{1}{10}c is the velocity of the electron (we are told it is 1/10 the speed of light c=3(10)^{8}\frac{m}{s})

This means equation (2) can be written as:

p=m_{e}\frac{1}{10}c   (3)

Substituting (3) in (1):

\lambda=\frac{h}{m_{e}\frac{1}{10}c}    (4)

\lambda=10\frac{h}{m_{e} c}    (5)

Now, we only have to find \lambda:

\lambda=10\frac{6.626(10)^{-34}\frac{m^{2}kg}{s}}{(9.11(10)^{-31}kg)(3(10)^{8}\frac{m}{s})}     (6)

<u>Finally:</u>

\lambda=2.42(10)^{-11} m>>> This is the de Broglie wavelength of an electron.

6 0
4 years ago
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