Can someone help plzzz asappp :///
2 answers:
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if we zero out f(x), namely make y = 0, we can get the roots or x-intercepts for this quadratic equation
now, the equation is in x-terms, meaning is a vertically opening parabola, so the axis of symmetry will be x = something, a vertical line.
well, we have two x-intercepts, one at -4 and another at 2, and the vertex is right half-way between those guys
-4------------(-1)------------2
so the vertex is at x=-1, namely the axis of symmetry is x = -1.
Answer:
B'(16,14)
Step-by-step explanation:
First find the coordinates of the vertex B. The center of the square M is the midpoint of the diagonal AC. Since A(2,7) and C(8,1), the center has coordinates
Point M is also the midpoint of the diagonal BD. Let B has coordinates (x,y), then
Hence, B(8,7).
Now, the dilation by a scale factor 2 with the center of dilation at the origin has the rule
(x,y)→(2x,2y).
Thus,
B(8,7)→B'(16,14).