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pashok25 [27]
3 years ago
15

Can someone help plzzz asappp :///

Mathematics
2 answers:
kow [346]3 years ago
8 0

Answer:

I believe answer choice A

Step-by-step explanation:

kati45 [8]3 years ago
6 0

Answer:

I thin that the answer is A

Step-by-step explanation:

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What is the y coordinate of the point where a graph crosses the y axis called ?
UNO [17]

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y-interspet  i think

Step-by-step explanation:

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3 years ago
16) What is the percent of increase from 15 to 60?
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400%

Step-by-step explanation:

3 0
3 years ago
Use the matrix tool to solve the system of equations. Choose the correct ordered pair.3x + 5y = 42 6x + 5y = 54
kobusy [5.1K]
Solutions  

In Matrix we use initially based on systems of linear equations.The matrix method is similar to the method of Elimination as but is a lot cleaner than the elimination method.Solving systems of equations by Matrix Method involves expressing the system of equations in form of a matrix and then reducing that matrix into what is known as Row Echelon Form.<span> 

Calculations 

</span>⇒ <span>Rewrite the linear equations above as a matrix 
</span>
\left[\begin{array}{ccc}3&5&42\\6&5&54\\\end{array}\right] 

⇒  Apply to Row₂ : Row₂ - 2 <span>Row₁ 
</span>
\left[\begin{array}{ccc}3&5&42\\0&-5&-30\\\end{array}\right] 

⇒ <span>Simplify rows
</span>
\left[\begin{array}{ccc}3&5&42\\0&1&6\\\end{array}\right] 

Note: The matrix is now in echelon form.
<span>The steps below are for back substitution. 
</span>
⇒ Apply to Row₁<span> : Row</span>₁<span> - </span>5 Row₂ 

\left[\begin{array}{ccc}3&0&12\\0&1&6\\\end{array}\right] 

⇒ <span>Simplify rows 
</span>
\left[\begin{array}{ccc}1&0&4\\0&1&6\\\end{array}\right] 

⇒ <span>Therefore, 
</span>
x=4&#10;&#10;y = 6
<span> 

 
</span>

5 0
3 years ago
Simplify the polynomial by combining like terms
Veseljchak [2.6K]

Answer:

22 x^2

Step-by-step explanation:

Simplify the following:

11 x^2 + 11 x^2

Hint: | Add like terms in 11 x^2 + 11 x^2.

11 x^2 + 11 x^2 = 22 x^2:

Answer:  22 x^2

none of your answers are correct.

8 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
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