Answer:
We conclude that an equation in slope-intercept form for the line that passes through (-3,5) and is perpendicular to the graph of y+2x=4 will be:
Step-by-step explanation:
Given the line
y+2x=4
converting into the slope-intercept form y = mx+b where m is the slope
y = -2x+4
comparing with the slope-intercept form
Thus, the slope is: m = -2
We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:
slope = m = -2
The slope of the new line perpendicular to the given line = – 1/m
= -1/-2 = 1/2
Using the point-slope form
where m is the slope of the line and (x₁, y₁) is the point
substituting the values m = 1/2 and the point (-3, 5)
Add 5 to both sides
Therefore, we conclude that an equation in slope-intercept form for the line that passes through (-3,5) and is perpendicular to the graph of y+2x=4 will be:
Answer: $49,000
Step-by-step explanation:
Total earnings = Basic salary + commission
Commission = 175,000 * 4%
= $7,000
Total earnings = 42,000 + 7,000
= $49,000
i would solve 4x-y =3 for y because the coefficient for y is 1
subtract 4x from each side
-y = -4x+3
divide by -1
y = 4x-3
Step-by-step explanation:
set that width is x
and length become 2X
P = 2×( X+ 2X )
200 = 6 X
X=33. 3
width = 33.3 inch
length = 66. 6 inch
Answer:
The 90% confidence interval is (493.1903, 550.2097), and the critical value to construct the confidence interval is 2.0150
Step-by-step explanation:
Let X be the random variable that represents a measurement of helium gas detected in the waste disposal facility. We have observed n = 6 values, 
= 521.7 and S = 31.6368. We will use
as the pivotal quantity. T has a 
distribution with 5 degrees of freedom. Then, as we want a 90% confidence interval for the mean level of helium gas present in the facility, we should find the 5th quantile of the t distribution with 5 degrees of freedom, i.e., 
, this value is -2.0150. Therefore the 90% confidence interval is given by
, i.e.,
(493.1903, 550.2097)
To find the 5th quantile of the t distribution with 5 degrees of freedom, you can use a table from a book or the next instruction in the R statistical programming language
qt(0.05, df = 5)
