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makkiz [27]
3 years ago
10

Determine which of the following expressions are part of the greatest common factor of 54 mrt and 27 mr. Select all

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
7 0

Answer:

All situations from 54 and 27 mr and mrt are apsrt of the greatest comon factor

Step-by-step explanation:

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The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true
Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478

<u>Part B</u>

P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767

<u>Part C</u>

\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971

6 0
2 years ago
Assume that two chords in a given circle are the same distance from the
Alenkinab [10]

Step-by-step explanation:

If the two chords are congruent, then they must be equidistant from the centre of the circle.

Answer: <u><em>D) They must be perpendicular</em></u>

A is rejected because the chord might not pass through the center of the circle.

B is rejected because the chords are not obligated to be parallel.

C is rejected because it is not compulsory for the chords to be perpendicular.

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3 years ago
Read 2 more answers
60% of a number is 567. what is 50% of the number
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Answer:

945

Step-by-step explanation:

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3 years ago
A square is inscribed In a circle with radius 6<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20" id="TexFormula1" title="
34kurt

Answer:

48 in

Step-by-step explanation:

The diagonal of the inscribed square equals the diameter of the circle.

1. Calculate the diagonal of the square

d = 2r = 2 × 6√2 in =12√2 in

2. Calculate the side of the square

∆ACB is an isosceles right triangle.

We can use Pythagoras' Theorem to calculate the length of a side s.

\begin{array}{rcl}s^{2} + s^{2} & = & (12\sqrt{2})^{2}\\2s^{2} & = & 144 \times 2\\s^{2} & = & 144\\s & = & \text{12 in}\\\end{array}

3. Calculate the perimeter of the square

P = 4s = 4 × 12 in = 48 in

The perimeter of the square is 48 in.

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For line A, y=1/6x

For line C, y=-2/7x+9

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