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a_sh-v [17]
3 years ago
13

HeLp PlsSsSsSsSsSsSsSsSsSs

Mathematics
2 answers:
klasskru [66]3 years ago
4 0

Answer:

51 to 6

Step-by-step explanation:

Zolol [24]3 years ago
4 0

Answer:

8.5 to 1

Step-by-step explanation:

The unit rate is $8.5 per 1 hour.

So, the ratio is 8.5 : 1

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Solving systems of linear equations by graphing 2x+3y=-12 and 10x+3y=12
Artyom0805 [142]

Answer:

  (x, y) = (3, -6)

Step-by-step explanation:

I like a good graphing calculator for solving systems of equations by graphing.

__

If you're solving these by hand, you need to graph the equations. It can be convenient to put the equations into "intercept form" so you can use the x- and y-intercepts to draw your graph.

That form is ...

  x/(x-intercept) +y/(y-intercept) = 1

Dividing a standard-form equation by the constant on the right will put it in this form.

  x/(-12/2) +y/(-12/3) = 1 . . . . . . divide the first equation by -12

  x/(-6) +y/(-4) = 1 . . . . . . . . . . . the x-intercept is -6; the y-intercept is -4

__

  x/(12/10) +y/(12/3) = 1 . . . . . . divide the second equation by 12

  x/1.2 +y/4 = 1 . . . . . . . . . . . . . the x-intercept is 1.2*; the y-intercept is 4

__

The locations of these intercepts and the slopes of the lines tell you that the solution will be in the fourth quadrant. The lines intersect at (x, y) = (3, -6).

_____

* It can be difficult to draw an accurate graph using an intercept point that is not on a grid line. It may be desirable to put the second equation into slope-intercept form, so you can see the rise/run values that let you choose grid points on the line. That equation is y =-10/3x +4. A "rise" of -10 for a "run" of +3 will get you to (3, -6) starting from the y-intercept of (0, 4).

4 0
3 years ago
1
insens350 [35]
The first appear is c must help you out
4 0
3 years ago
9-2x=35<br> Help Me please
denis-greek [22]

Answer: x=24

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
I NEED HELP <br><br> THERE ARE TWO OTHER QUESTIONS AS WELL
Temka [501]

Answer:

Please find attached the drawing of ABCD, A'B'C'D', and A''B''C''D'', created with MS Excel

Step-by-step explanation:

The given composition of transformation is r_{y-axis} \ \circ \ r_{x = - 4}

The transformation on the right, r_{x = - 4}, is carried out first as follows;

The point <em>A</em> with coordinate (-7, 7) reflected across the line x = -4, gives;

A(-7, 7) r_{x = - 4}<em> </em>→ A'(-1, 7)

Similarly, we have;

B(-5, 7) r_{x = - 4} → B'(-3, 7)

C(-5, 1) r_{x = - 4} → C'(-3, 1)

D(-7, 1) r_{x = - 4} → D'(-1, 1)

Therefore, the image of the given rectangle after reflection across the lie, x = -4, is A'(-1, 7), B'(-3, 7), C'(-3, 1), and D'(-1, 1)

The second transformation, r_{y-axis}, is found as follows;

(x, y) r_{y-axis} → (x, -y)

Therefore, we have;

A'(-1, 7) r_{y-axis} → A''(-1, -7)

B'(-3, 7) r_{y-axis} → B''(-3, -7)

C'(-3, 1) r_{y-axis} → C''(-3, -1)

D'(-1, 1) r_{y-axis} → D''(-1, -1)

The points ABCD, A'B'C'D', and A''B''C''D'' are plotted on MS Excel and the points joined with straight lines to form the drawing of the triangles as shown in the attached figure.

5 0
3 years ago
If cos60 degrees= 3root/2 find the sin60 degree
postnew [5]
This is the
Hopefully I answered correctly

5 0
3 years ago
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