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liubo4ka [24]
3 years ago
14

In the parallelogram below, z = ?°

Mathematics
1 answer:
katrin [286]3 years ago
7 0

Answer:

z is 111 degrees

Step-by-step explanation:

69 ° and z is a linear pair, therefore:

69 + z = 180

z = 180 - 69

z= 111

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If you plot and connect these points P1(3,2) and P2(6,8) , what figure is Formed? What is the Direction?
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Please check the explanation.

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  • P2(6, 8)

When we plot P1(3, 2) and P2(6, 8), we determine the line segment P1P2.

The direction of the segment is from P1 to P2.

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\:l=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

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Thus, the length of the segment is:

\:\:\:l=3\sqrt{5}

Determining the equation of a line containing the segment P1P2

Given the points

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  • P2(6, 8)

Finding the slope between P1(3, 2) and P2(6, 8)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(3,\:2\right),\:\left(x_2,\:y_2\right)=\left(6,\:8\right)

m=\frac{8-2}{6-3}

m=2

Using the line point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where m is the slope of the line and (x₁, y₁) is the point

substituting the values m = 2 and the point (3, 2)

y-2=2\left(x-3\right)

Add 2 to both sides

y-2+2=2\left(x-3\right)+2

y=2x-4

Thus, the equation of a line containing the line segment P1P2 is:

y=2x-4

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