3 years ago

Parallel lines have the same slope

Mathematics

2 answers:

Svetradugi [14.3K]3 years ago

6 0

This question is true!

DENIUS [597]3 years ago

6 0

True.

Any and all lines that are parallel share the same slope.

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Simplify negative 9 over 6 divided by 3 over negative 2. . (5 points) a 3 b 1 c −1 d −3

vladimir2022 [97]

Answer:

b) 1

Step-by-step explanation:

$\frac{9}{6} \times \frac{2}{3} = \frac{18}{18}$

$\frac{18}{18} = 1$

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1640 km every hour is the answer

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Svetach [21]

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3 years ago

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Answer:

Step-by-step explanation:

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6 0

2 years ago

three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal

Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

= x + x + (x + $\frac{6}{5}$ ) = $\frac{27}{4}$

= 3x + $\frac{6}{5}$ = $\frac{27}{4}$

= 3x = $\frac{27}{4}$ - $\frac{6}{5}$

( let's take the LCM of 4 and 5 = 20

= 3x = $\frac{135}{20}$ - $\frac{24}{20}$

= 3x = $\frac{111}{20}$

= x = $\frac{111}{20}$ ÷ $\frac{3}{1}$ = $\frac{111}{20}$ × $\frac{1}{3}$ = $\frac{37}{20}$

So, the weight of the equal bags are $\frac{37}{20}$ and the weight of the third bag ( heavy one ) is $\frac{37}{20}$ + $\frac{6}{5}$ = $\frac{37}{20}$ + $\frac{24}{20}$ = $\frac{61}{20}$

1st bag = $\frac{37}{20}$ kg

2nd bag = $\frac{37}{20}$ kg

3rd bag = $\frac{61}{20}$ kg

Hope it helps...

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3 years ago