All categories

3 years ago

The temperature was recorded at the same time each day,

Mathematics

1 answer:

kozerog [31]3 years ago

4 0

Answer:

a) The warmest temperature will be the one where the value of the temperature is the largest, in the table we can see that the largest temperature is 3°C on Saturday.

Then the largest temperature was on Saturday, and it was 3°C

b) Which temperature was the coldest?

Now we need to look at the smallest temperature (or the largest negative temperature). In the table we can see that the smallest temperature is -6°C on Friday.

Then the smallest temperature is -6°C.

c) On Thursday the temperature was -1°C

On Saturday the temperature was 3°C

The difference between the temperatures is:

-1°C - (3°C) = -4°C

This means that Thursday was -4°C colder than on Saturday.

d) On Sunday, the temperature was 5°C lower than on Saturday.

On Saturday the temperature was 3°C, then the temperature on Sunday is:

T = 3°C - 5°C = -2°C

The temperature on Sunday is -3°C.

You might be interested in

Marley is a waitress. On Thursday, she earned $4.60 per hour plus $50.25 in tips. How many hours did she work that day if she ea

ELEN [110]

Answer:

8 hours

Step-by-step explanation:

1. Subtract value of tips she got that day

87.05 - 50.25 = 36.8

36.8 is the actual payment for her job that day

2. Divide 36.8 with paid/hour (4.6)

36.8 ÷ 4.6 = 8 hours

8 0

3 years ago

Help thank you but quick due date is soon

hammer [34]

Answer:

If you reflect point x across the y axis, it will end up at (-1/2,0).

Step-by-step explanation:

5 0

3 years ago

A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

5 0

3 years ago

Question:

snow_tiger [21]

Answer:

A (first picture)

Step-by-step explanation:

Based on the picture, the lines are both perpendicular and the red line splits AB into two equal parts (bisects it), so it must represent the perpendicular bisector of AB.

5 0

3 years ago

Farmer Joe is planning to fence in a garden area in a portion of his field which is 75 feet wide. The farmer would like to creat

LenKa [72]

He could make his plot 300 feet long

5 0

3 years ago