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Vikentia [17]
3 years ago
12

A 9 kg blob moving at 5 m/s collides and sticks to a second blob with a mass of 5 kg. If the two bobs stick together, what will

the velocity of the two blobs move at?
Physics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

the final velocity of the two blobs after collision is 3.21 m/s.

Explanation:

Given;

mass of first blob, m₁ = 9 kg

mass of the second blob, m₂ = 5 kg

initial velocity of the first blob, u₁ = 5 m/s

initial velocity of the second blob, u₂ = 0

Let the final velocity of the two blobs after collision = v

Apply the principle of conservation linear momentum to determine v;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

9 x 5   +    5 x 0 = v(9 + 5)

45 = 14v

v = 45 / 14

v = 3.21 m/s

Therefore, the final velocity of the two blobs after collision is 3.21 m/s.

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Both lead and zinc are formed as precipitates. Which of these is a step in the formation of the minerals?
Ahat [919]
Minerals are naturally occurring inorganic (they're not formed from amino acids, peptides, or enzymes) chemical compounds.

From the given options, the following describes a step in the formation of the minerals: materials break up due to rise in temperature.

Correct answer: D

5 0
3 years ago
If you accelerate from rest at 12m/s^2 for 5 seconds, what is your finally velocity?
jeka94

Answer:

v=60m/s

Explanation:

Use the Kinematic Equation:

v=v_o+at

Plug in what is given and solve

v=0+(12)(5)

v=60m/s

3 0
2 years ago
When you put the iron cube in the olive oil and the brick cube in the water what loses heat more quickly and why? The oil or the
andrezito [222]

Answer:

HUH

Explanation:

6 0
3 years ago
A cart of mass m = 0.12 kg moves with a speed v = 0.45 m/s on a frictionless air track and collides with an identical cart that
lina2011 [118]

Answer:

0.006075Joules

Explanation:

The final kinetic energy of the system is expressed as;

KE = 1/2(m1+m2)v²

m1 and m2 are the masses of the two bodies

v is the final velocity of the bodies after collision

get the final velocity using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

0.12(0.45) + 0/12(0) = (0.12+0.12)v

0.054 = 0.24v

v = 0.054/0.24

v = 0.225m/s

Get the final kinetic energy;

KE = 1/2(m1+m2)v

KE = 1/2(0.12+0.12)(0.225)²

KE = 1/2(0.24)(0.050625)

KE = 0.12*0.050625

KE = 0.006075Joules

Hence the final kinetic energy of the system is 0.006075Joules

5 0
2 years ago
An electric field of intensity 3.80 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.
lakkis [162]

Answer: 1.55 x 10⁴ Nm²c^-1

Explanation: The electric flux, electric field intensity and area are related by the formulae below.

Φ= EAcosθ,

Where Φ= electric flux (Nm²c^-1)

E =electric field intensity (N/m²)

A = Area (m²)

θ= this is angle between the planar area and the magnetic flux

For our question E=3.80KN/c= 3800 N/c

A= 0.700 x 0.350= 0.245m²

θ= 0° ( this is because the electric field was applied along the x axis, thus the electric flux will be parallel to the area).

Hence Φ= 3800 x 0.245 x cos(0)

= 3800 x 0.245 x 1 (value of cos 0° =1)

= 1.55 x 10⁴ Nm²c^-1

Thus the electric field is 1.55 x 10⁴ Nm²c^-1

4 0
3 years ago
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