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Vikentia [17]
3 years ago
12

A 9 kg blob moving at 5 m/s collides and sticks to a second blob with a mass of 5 kg. If the two bobs stick together, what will

the velocity of the two blobs move at?
Physics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

the final velocity of the two blobs after collision is 3.21 m/s.

Explanation:

Given;

mass of first blob, m₁ = 9 kg

mass of the second blob, m₂ = 5 kg

initial velocity of the first blob, u₁ = 5 m/s

initial velocity of the second blob, u₂ = 0

Let the final velocity of the two blobs after collision = v

Apply the principle of conservation linear momentum to determine v;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

9 x 5   +    5 x 0 = v(9 + 5)

45 = 14v

v = 45 / 14

v = 3.21 m/s

Therefore, the final velocity of the two blobs after collision is 3.21 m/s.

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Which meteorites are the most useful for defining the age of the solar system? Why?
scoundrel [369]

Answer:

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Explanation:

the meteorites which are most useful for the determination of the age of the solar system are the primitive meteorites. they consist light of colored or grey silicates mixed with metallic grains. the parent bodies of these meteorites are also mostly believed to be pieces asteriods left after they formed in the solar system.

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2 years ago
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If you weigh 690 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun an
lana [24]

Answer:

Explanation:

Given that,

Mass of star M(star) = 1.99×10^30kg

Gravitational constant G

G = 6.67×10^−11 N⋅m²/kg²

Diameter d = 25km

d = 25,000m

R = d/2 = 25,000/2

R = 12,500m

Weight w = 690N

Then, the person mass which is constant can be determined using

W =mg

m = W/g

m = 690/9.81

m = 70.34kg

The acceleration due to gravity on the surface of the neutron star is can be determined using

g(star) = GM(star)/R²

g(star) = 6.67×10^-11 × 1.99×10^30 / 12500²

g (star) = 8.49 × 10¹¹ m/s²

Then, the person weight on neutron star is

W = mg

Mass is constant, m = 70.34kg

W = 70.34 × 8.49 × 10¹¹

W = 5.98 × 10¹³ N

The weight of the person on neutron star is 5.98 × 10¹³ N

5 0
3 years ago
A runner traveling with an initial velocity of 1.1 m/s accelerates at a constant rate of 0.8 m/s2fora time of 2.0 s.(a).What is
pychu [463]

Answer:

The final velocity of the runner at the end of the given time is 2.7 m/s.

Explanation:

Given;

initial velocity of the runner, u = 1.1 m/s

constant acceleration, a = 0.8 m/s²

time of motion, t = 2.0 s

The velocity of the runner at the end of the given time is calculate as;

v = u + at

where;

v is the final velocity of the runner at the end of the given time;

v = 1.1 + (0.8)(2)

v = 2.7 m/s

Therefore, the final velocity of the runner at the end of the given time is 2.7 m/s.

7 0
2 years ago
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