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Vikentia [17]
3 years ago
12

A 9 kg blob moving at 5 m/s collides and sticks to a second blob with a mass of 5 kg. If the two bobs stick together, what will

the velocity of the two blobs move at?
Physics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

the final velocity of the two blobs after collision is 3.21 m/s.

Explanation:

Given;

mass of first blob, m₁ = 9 kg

mass of the second blob, m₂ = 5 kg

initial velocity of the first blob, u₁ = 5 m/s

initial velocity of the second blob, u₂ = 0

Let the final velocity of the two blobs after collision = v

Apply the principle of conservation linear momentum to determine v;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

9 x 5   +    5 x 0 = v(9 + 5)

45 = 14v

v = 45 / 14

v = 3.21 m/s

Therefore, the final velocity of the two blobs after collision is 3.21 m/s.

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Who discovered laws of gravity and motion? He discovered aspects of light and color, leading to today's spectrum analysis
Vitek1552 [10]

Answer:

Sir Isaac Newton

Explanation:

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A basketball has a mass of 609 g. Moving to the right and heading downward at an angle of 32° to the vertical, it hits the floor
andrezito [222]

Answer:1.549 kg-m/s

Explanation:

Given

mass of basketball =609 g

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where u=3m/s

v=3m/s

m=mass of ball

P_x=0

Change in momentum in Y-direction

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The metric system is based on units of tens.
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A circular wire loop 51 cm in diameter has resistance 120 ω and lies in a horizontal plane. a uniform magnetic field points vert
Irina18 [472]
The radius of the wire loop is r= \frac{51 cm}{2}= 25.5 cm=0.255 m, so the area enclosed by the loop is
A=\pi r^2 = \pi (0.255 m)^2=0.204 m^2

Initially, the magnetic field intensity is B=5.0 mT=0.005 T, so the magnetic flux throug the wire loop is
\Phi = BA=(0.005 T)(0.204 m^2)=1.02 \cdot 10^{-3} Wb

3 0
4 years ago
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