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Vikentia [17]
3 years ago
12

A 9 kg blob moving at 5 m/s collides and sticks to a second blob with a mass of 5 kg. If the two bobs stick together, what will

the velocity of the two blobs move at?
Physics
1 answer:
vazorg [7]3 years ago
6 0

Answer:

the final velocity of the two blobs after collision is 3.21 m/s.

Explanation:

Given;

mass of first blob, m₁ = 9 kg

mass of the second blob, m₂ = 5 kg

initial velocity of the first blob, u₁ = 5 m/s

initial velocity of the second blob, u₂ = 0

Let the final velocity of the two blobs after collision = v

Apply the principle of conservation linear momentum to determine v;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

9 x 5   +    5 x 0 = v(9 + 5)

45 = 14v

v = 45 / 14

v = 3.21 m/s

Therefore, the final velocity of the two blobs after collision is 3.21 m/s.

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4 0
3 years ago
Read 2 more answers
A ball is thrown vertically upwards at 19.6 m/s. for its complete trip (up and back down to the starting position), its average
Alex17521 [72]
The average velocity of an object is given by:
Average velocity = total displacement / total time

First, we calculate the time taken to reach the maximum height of the ball. This occurs when the final velocity is 0.
Vf = Vi + at
0 = 19.6 - 9.81 * t
t = 2 seconds

The total trip will be of 4 seconds (2 seconds up, 2 seconds down)

The total displacement is given by:
s = ut + 1/2 * at²
s = 19.6 * 2 - 0.5 * 9.81 * 2²
s = 19.6 meters

This is the distance maximum height, so the total height is
19.6 * 2 = 39.2 meters

Average velocity = 39.2 / 4
Average velocity = 9.8 m/s
5 0
3 years ago
You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the rea
KonstantinChe [14]

Answer : The half-life of this substance will be, 45 minutes.

Explanation :

First we have to calculate the value of rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = time passed by the sample  = 90.3 min

a = initial amount of the reactant = 400

a - x = amount left after decay process = 100

Now put all the given values in above equation, we get

k=\frac{2.303}{90.3min}\log\frac{400}{100}

k=1.54\times 10^{-2}\text{ min}^{-1}

Now we have to calculate the half-life of substance, we use the formula :

k=\frac{0.693}{t_{1/2}}

1.54\times 10^{-2}\text{ min}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=45min

Therefore, the half-life of this substance will be, 45 minutes.

4 0
3 years ago
Four 240 Ω light-bulbs are connected in series. What is the total resistance of the circuit? What is their resistance if they ar
irina [24]

Had to submit as image as it wouldn't let me paste these symbols in the answer box

hope this helps:)

5 0
3 years ago
When a current is passed through a coil of wire with a piece of iron inside (an electromagnet,a commutator) is formed?
ELEN [110]
When a current is passed through a coil of wire with a piece of iron inside, the one that will be formed is : 
an electromagnet
It happens when a soft metal core made into magnet by passage of electric current

hope this helps
6 0
4 years ago
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