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2 years ago

Does the following decrease or increase normal force? Pulling up on the object.

Physics

2 answers:

Maurinko [17]2 years ago

7 0

Answer:

babyyyy baby yay ohhhhh I live the tye sjshs

Sav [38]2 years ago

6 0

Answer:

gravy+gravity = time X nuclious so your ANSWER WILL BE gravity ;-;

Explanation:

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An atom emission of light with a specific amount of energy confirms that ?

marusya05 [52]

The correct answer is B, electrons emit and absorb energy based on their position around the nucleus.

8 0

2 years ago

Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A stationary police car emits a sound of frequen

bixtya [17]

Answer:

a) The velocity of the car is 7.02 m/s and the car is approaching to the police car as the frequency of the police car is increasing.

b) The frequency is 1404.08 Hz

Explanation:

If the police car is a stationary source, the frequency is:

$f_{a} =(\frac{v+v_{c} }{v} )f_{s}$ (eq. 1)

fs = frequency of police car = 1200 Hz

fa = frequency of moving car as listener

v = speed of sound of air

vc = speed of moving car

If the police car is a stationary observer, the frequency is:

$f_{L} =f_{a} (\frac{v}{v-v_{c} } )=(\frac{v+v_{c} }{v-v_{c} } )f_{s}$ (eq. 2)

Now,

fL = frequecy police car receives

fs = frequency police car as observer

a) The velocity of car is from eq. 2:

$1250=1200(\frac{v+v_{c} }{v-v_{c} } )\\1250(v-v_{c} )=1200(v+v_{c} )\\v_{c} =\frac{50*344}{2450} =7.02m/s$

b) Substitute eq. 1 in eq. 2:

$f_{L} =(\frac{v+v_{p} }{v-v_{c} } )(\frac{v+v_{c} }{v-v_{p} } )f_{s} =(\frac{344+20}{344-7.02} )(\frac{344+7.02}{344-20} )*1200=1404.08Hz$

7 0

2 years ago

a body dropped from a height reaches a velocity of 13m/s just before touching the ground. What is the initial height of the ball

SashulF [63]

Hi there!

We can use the following (derived) equation to solve for the final velocity given height:

vf = √2gh

We can rearrange to solve for height:

vf² = 2gh

vf²/2g = h

Plug in the given values (g = 9.81 m/s²)

(13)²/2(9.81) = 8.614 m

We can calculate time using the equation:

vf = vi + at, where:

vi = initial velocity (since dropped from rest, = 0 m/s)

a = acceleration (in this instance, due to gravity)

Plug in values:

13 = at

13/a = t

13/9.81 = 1.325 sec

5 0

1 year ago

Can someone answer pls??

SCORPION-xisa [38]

Answer:

2. the volume of the square are the same

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1 year ago

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A load of 500 N is placed 8 N from the pivot what is the turning moment of the load

Nataliya [291]

The answer is 4000N...

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2 years ago