How much heat is absorbed by a 35g iron skillet when its temperature rises from 14oC to 79oC? Joules

1 answer:

7 0

Data:
Q (Amount of heat) = ?(in Joule)
m (mass) = 35 g
c (Specific heat of iron) = 0.45 J/(g × ° C)
T (final) = 79 ºC
To (initial) = 14 ºC
ΔT = T - To → ΔT = 79 - 14 → ΔT = 65 ºC

Formula:
Q = m*c*ΔT

Solving:
Q = m*c*ΔT
Q = 35*0.45*65
$\boxed{\boxed{Q = 1023.75\:Joules}}\end{array}}\qquad\quad\checkmark$

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2. Three super strong teenagers pull a heavy crate across the floor. Dion pulls with a force of 18.5 N towards 0°. Shirley pulls

kogti [31]

Answer:

A) The resultant force is 43.4 [N]

B) The movement of the heavy crate is going to the right and in the negative direction on the y-axis

Explanation:

We need to make a sketch of the different forces acting on the heavy crate.

In the attached image we can see the forces and the sum of the vector with their respective angles.

Forces in the X-axis

$Fdionx=18.5N\\\\Fshix=16.5*cos(30)=14.29N\\Fjoanx=19.5*cos(60)=9.75N\\\\Forcex= 18.5 + 14.29 + 9.75 = 42.54 N$

Forces in the y-axis

$FDiony=0[N]\\Fshirley= 16.5*sin(30)=8.25[N]\\Fjoany=19.5*sin(60)=16.88 [N]\\\\Forcesy=0+8.25-16.88= -8.63[N]$

Using the Pythagorean theorem

$Tforce=\sqrt{(42.54)^{2} +(8.63)^{2} } \\\\Tforce= 43.4N$

The movement of the heavy crate is going to the right and in the negative direction on the y-axis, this can be easily seen in the graphical sum of vectors.