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timama [110]
3 years ago
15

The Newton is the SI unit for ____. temperature mass weight density

Physics
1 answer:
mel-nik [20]3 years ago
7 0

Answer:

weight

Explanation:

weight is measurd in newtons (N)

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A 4.8-kg block attached to a spring executes simple harmonic motion on a frictionless horizontal surface. At time t=0 s, the blo
garri49 [273]

Answer:

E) 80 N/m

Explanation:

Given;

mass of the block, m = 4.8 kg

displacement of the block, x = -0.5 m

velocity of the block, v = -0.8 m/s

acceleration of the block, a = 8.3 m/s²

From Newton's second law of motion;

F = ma

Also, from Hook's law;

F = -Kx

where;

k is the force constant

Thus, ma = -kx

k = -ma/x

k = -(4.8 x 8.3) / (-0.5)

k = 79.7 N/m

k ≅ 80 N/m

Therefore, the force constant of the spring is closest to 80 N/m

4 0
3 years ago
Science help? 50 POINTS!
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1. Volcanoes and minor earthquakes

2. Volcanoes, earthquakes and fold mountains.

3. Earthquakes and fold mountains.

4. Magma from volcanoes is filled with nutrients that makes land fertile.


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7 0
4 years ago
Read 2 more answers
Which circuit would have the most electrical power? O A. 1 = 3.2 A V = 0.12 V OB. 1 = 2.5 A V = 0.22 OC 1=3.3 A V=0.09 V OD 1 =
Alja [10]

Answer:

(not real answer)

Explanation:

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3 years ago
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Two tougboats are toeing a ship each exerts a force of 6000N and the angle between the two ropes is 60 calculate the resultant f
Arlecino [84]

Answer:

10392.30N

Explanation:

We proceed by computing the individual force exerted by the boats

For the first boat

The angle is 30 degree to the vertical

Hence

Force = F cos θ

F=6000 cos 30

F=6000*0.866

F=5196.15 N

Since the boats are two and also at the same angle and also exerting the same force

The Net force = 2*5196.15

Net force=10392.30N

7 0
3 years ago
A charge of 4 nc is placed uniformly on a square sheet of nonconducting material of side 17 cm in the yz plane. (a) what is the
Ratling [72]

The charge density of the sheet is 1.384×10⁻⁷C/m².

Charge density is defined as the charge per unit area.

The sheet is a square of length  l=17 cm.

Calculate the area A of the sheet .

A=l^2=(17 cm)^2= (17*10^-^2m)^2=0.0289 m^2

The charge Q on the sheet is

Q=4nC=4*10^-^9C

The charge density σ is given by,

\sigma=\frac{Q}{A}

Substitute 4×10⁻⁹C for Q and 0.0289 m² for A.

\sigma=\frac{Q}{A}\\ =\frac{4*10^-^9C}{0.0289 m^2} \\ =1.389*10^-^7C/m^2

Thus, the charge density of the sheet is <u>1.384×10⁻⁷C/m².</u>

8 0
4 years ago
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