The number of oxygen atoms that are in 4 Al₂O₃ are 12 atoms
<u><em> Explanation</em></u>
- The subscript in a chemical formula indicate the number of atoms of element immediately before the subscript.
- coefficient is the number in front of the formula and tells us how many molecules of a given formula are present.
- Since 4Al₂O₃ has coefficient of 4 and the subscript of O is 3 the number of O atoms = 4 x 3=12 atoms
A is the answer. I hope this helps
Answer : The mass of calcium chloride is, 116.84 grams
Solution : Given,
Molar mass of calcium chloride, = 110.98 g/mole
Number of molecules of calcium chloride =
As we know that,
1 mole of calcium chloride contains molecules of calcium chloride
or,
1 mole of calcium chloride contains 110.98 grams of calcium chloride
Or, we can say that
As, molecules of calcium chloride present in 110.98 grams of calcium chloride
So, molecules of calcium chloride present in of calcium chloride
Therefore, the mass of calcium chloride is, 116.84 grams
A Beta Particle is <span>a fast-moving electron emitted by radioactive decay of substances.</span>
Answer:
The entropy change for the vaporization of 18 grams of a hydrocarbon at its boiling point is 12.87 J/K.
Explanation:
Mass of hydrocarbon = 18 g
Molar mass of hydrocarbon = 114 g/mol
Moles of hydrocarbons =
The enthalpy of vaporization of hydrocarbon =
Heat required to heat 0.1579 moles of hydrocarbon = Q
Q = 4.263 kJ = 4,263 J ( 1 kJ = 1000 J)
Boiling point of hydrocarbon = T = 58.2°C = 58.2 + 273 K = 331.2 K
Entropy change for the vaporization of 18 g of a hydrocarbon:
The entropy change for the vaporization of 18 grams of a hydrocarbon at its boiling point is 12.87 J/K.