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My name is Ann [436]
3 years ago
9

A brick of pure silver is divided into 4 pieces of equal size. Compared to the original brick, the density of each piece is ____

_.
4 times larger

4 times smaller

the same

16 times smaller
Chemistry
1 answer:
AnnyKZ [126]3 years ago
8 0

Answer:

brick of pure silver is divided into 4 pieces of equal size. Compared to the original brick, the density of each piece is _____.

:- the same

Explanation:

Density of the substance is the mass per unit volume of the substance.

Density =\frac{mass}{volume}

Let the original mass of the brick = m

let the volume of the brick = V

Density =\frac{m}{V}

when A brick of pure silver is divided into 4 pieces of equal size.Its mass become 1/4 time the original mass and volume also become 1/4

New mass = 1/4 m

Volume = 1/4  V

Density =\frac{m/4}{V/4}

4 and 4 cancel each other

Density =\frac{m}{V}

Hence, <u>No change in density</u> of the brick will occur if we divide into for equal pieces.

Such quantities are called Intensive properties .

Intensive property : Which does not depend on the quantity of the matter .example : Temperature , density ,specific Heat capacity.

There is no effect of change of either mass or volume on density.

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3 years ago
n an experiment, 39.26 mL of 0.1062 M NaOH solution was required to titrate 37.54 mL of \ v unknown acetic acid solution to a ph
olasank [31]

Answer:

Molarity: 0.111M

% (w/w): 0.666

Explanation:

The reaction of NaOH with acetic acid (CH₃COOH) is:

NaOH + CH₃COOH → CH₃COO⁻Na⁺ + H₂O

<em>where 1 mole of NaOH reacts per mole of acetic acid producing 1 mole of water and 1 mole of sodium acetate.</em>

As 39.26mL ≡ 0.03926L of 0.1062M are required to titrate the solution of acetic acid. Moles are:

0.03926L × (0.1062mol / L) = 4.169x10⁻³ moles of NaOH. As 1 mole of NaOH reacts per mole of acetic acid:

4.169x10⁻³ moles of CH₃COOH.

Molarity is defined as ratio between moles of substance and volume of solution in liters. Thus, molarity of acetic acid solution is:

4.169x10⁻³ moles of CH₃COOH / 0.03754L = <em>0.111M</em>

<em></em>

As molar mass of acetic acid is 60g/mol, 4.169x10⁻³ moles weights:

4.169x10⁻³ moles × (60g / mol) = <em>0.2501 g of acetic acid</em>

Now, assuming density of solution as 1.00g/mL, 37.54mL weights <em>37.54g</em>.

Thus, percent by weight is:

0.2501g CH₃COOH / 37.54g × 100 = <em>0.666% (w/w)</em>

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<u>Hence, moles of CO_2 when 1 mole of wax, C_{31}H_{64} is burnt = 31 moles</u>

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