Answer:
0.00353J/g/°C
Explanation:
I will assume the temperature of the ice to be approximately 0°C.
Moreover, Heat of fusion of water is 6kJ
Amount of heat used to melt 5.3g of ice = 5.3 x 6 / 18
=1.767g°C
Therefore
1.767 = 25 x specific heat cap. x 200
Specific heat cap. = 1.767/(25x200)
= 0.00353J/g/°C
Answer:
Its phosphorus (P)
Explanation:
In writing the electron configuration for Phosphorus the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for Phosphorous go in the 2s orbital. The next six electrons will go in the 2p orbital. The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s. Since the 3s if now full we'll move to the 3p where we'll place the remaining three electrons. Therefore the Phosphorus electron configuration will be 1s22s22p63s23p3.
<em><u>the</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>neutrons</u></em><em><u> </u></em><em><u>i</u></em><em><u>n</u></em><em><u> </u></em><em><u>aluminium</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>1</u></em><em><u>4</u></em>
Answer:
They test it using the scientific method.
