The chemical symbol for sodium bicarbonate is NaHCO3. Its molar mass is 84 g/mol. In each of one mol of sodium bicarbonate their is one mole of carbon dioxide with the molar mass of 44 grams per mol. We determine the number of moles in 0.10 g of sodium bicarbonate.
n sodium bicarbonate = (0.10 g) / (84 grams / mol)
= 1.19 x 10-3 moles sodium bicarbonate
Therefore, there are also 1.19 x 10-3 moles of carbon dioxide.
Answer:
Relation between , molality and temperature is as follows.
T =
It is also known as depression between freezing point where, i is the Van't Hoff factor.
Let us assume that there is 100% dissociation. Hence, the value of i for these given species will be as follows.
i for = 3
i for glucose = 1
i for NaCl = 2
Depression in freezing point will have a negative sign. Therefore, d
depression in freezing point for the given species is as follows.
=
=
=
Therefore, we can conclude that given species are arranged according to their freezing point depression with the least depression first as follows.
Glucose < NaCl <
Explanation: