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tigry1 [53]
3 years ago
13

A flask contains 0.100 mol of liquid bromine, br2. determine the number of bromine molecules present in the flask.

Chemistry
1 answer:
irakobra [83]3 years ago
8 0
Avagadros number is where 1 mol of any substance is made of 6.022 x 10²³ units. These units could be atoms making up an element of molecules making up a compound.
1 mol of Br₂ is made of 6.022 x 10²³ molecules of Br₂
the flask contains 0.100 mol
Therefore if 1 mol has 6.022 x 10²³ molecules of Br₂
then 0.1 mol has - 6.022 x 10²³ molecules/mol x 0.1 mol 
therefore number of molecules - 6.022 x 10²² Br₂ molecules ₂
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1.<br> Draw the Dot Structure for Na!
stepladder [879]

Answer:

Na ·

Explanation:

Hello!

In this case, since the Lewis dot structure of any element illustrates the number of valence electrons at the outer shell; we can set up the electron configuration of sodium to obtain:

Na^1^1\rightarrow 1s^2,2s^2,2p^6,3s^1

We can see there is only one valence electron, for that reason the Lewis dot structure is:

Na ·

Whereas the dot represents the valence electron.

Best regards!

4 0
3 years ago
Cyclopropene decomposes to propene when heated to 500 C, calculate rate constant for the first order reaction 0 min 1.48 mmol/L
Dmitry_Shevchenko [17]

Answer:

k = 0.0306 min-1

Explanation:

The table is given as;

Time, Concentration

0 1.48

5 1.27

10 0.98

15 0.84

The integrated rate law for a first order reaction is given as;

ln [A] = -kt + ln [Ao]

where;

[A] = Final Concentration

[Ao] = Initial Concentration

k = rate constant

t = time

In the table, taking the first two sets of values;

t = 5

k = ?

[Ao]  = 1.48

[A] = 1.27

Inserting into the equation;

ln(1.27) = - k (5) + ln(1.48)

ln(1.27)  - ln(1.48) = -5k

-0.1530 = -5k

k = -0.1530 / -5

k = 0.0306 min-1

6 0
3 years ago
How many significant figures are in the quantity 12.0 mL?<br> O A. 1<br> B. 2<br> C. 3<br> O D. 12
insens350 [35]

Answer:

C. 3

Explanation:

12.0 - 3 significant figures 1,2 and 0, because 0 is after decimal point.

7 0
3 years ago
How many milliliters of .085 m naoh are required to titrate 25 ml of .072 m hbr to the equivalence point?
SOVA2 [1]
The ML  of 0.85  m NaOH    required   to  titrate  25 ml of  0.72m hbr  to  the  equivalence  point  is calculated  as  follows

calculate  the moles  of HBr used

moles  = molarity  x  volume

25  x0.072/1000=  0.0018 moles


write the  equation  for  reaction

NaOH + HBr = NaBr  +  H2O
from   reacting   equation the  mole ratio  between  NaOH  to  HBr  is  1:1  therefore  the  moles of  NaOH  =  0.0018 moles

volume   =  moles/molarity
0.0018/0.085 =  0.021  L  in Ml  =  0.021  x1000=21.18 Ml  ofNaOH

8 0
3 years ago
diagram 1 above shows equimolar samples of two gases inside a container fitted with a removable barrier placed so that each gas
vampirchik [111]

This problem is describing the state two gases have when separated and together as shown on the attached picture. First of all, diagram 1 shows how they are separated in two containers with apparently equal volumes, whereas diagram 2 shows the removal of the barrier so that they get mixed together.

In this case, we can analyze that each gas has its own pressure and due to the removal of the barrier, both pressure and volume undergo a change. Thus, we can infer that the final volume is doubled with respected to the initial one for each gas, causing the pressure of each gas to be halved and the total pressure the half of the added ones, in agreement to the Boyle's law (inversely proportional relationship between pressure and temperature).

Therefore, the correct choice is:

C. The partial pressure of each gas in the mixture is half its initial pressure; the final total pressure is half the sum of the initial pressures of the two gases.

Learn more:

  • brainly.com/question/21184611

8 0
3 years ago
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