The response
the point A(-6, 2)
we know that <span>-y+x ≤ -6, the point satisfying this is </span><span>A(-6, 2)
proof -2+ (-6) = -8 less than -6</span>
Answer:
IQR = 3
Step-by-step explanation:
Interquartile range, which is abbreviated as IQR, is just the difference between the upper quartile (where the box ends) and the lower quartile (where the box starts). AS it is given in the question that that box starts from 4 and ends at . The interquartile range IQR is simply:
IQR = 7 - 4 = 3
The values of data are usually clustured around some central value. Interquartile range tells us how spread out these middle values. It also tells when some values are too far from the central value. The values which are too far are also termed as outlier values
Answer: Y= -3/4x+13
Step-by-step explanation:
A line passes through the point (8,7) and has a slope of negative 3/4 Write an equation in slope-intercept form for this line.
This is what i get
Slope of a line Y= mx+b
Y= 7
X= 8
M= -3/4
7= -3/4(8)+b
7= -6+b
7+6=b
13=b
Y= -3/4x+13
The length of line in green = 5 cm
the length of line in yellow = 3 cm
the length of line in red = 6 cm
the length of line in white = 16 cm
the total area = 100 + 12 + 12 + 20 + 24 + 96 = 264 cm2
