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3 years ago

Answer please urgent

Physics

2 answers:

motikmotik3 years ago

5 0

Answer:

equal and unlike charges

Explanation:

LiRa [457]3 years ago

5 0

Answer:

$\huge\boxed{\sf Equal \ and \ unlike \ charges}$

Explanation:

When two bodies are rubs against each other, Charges of equal magnitude are induced in them. However, they are of equal magnitude but the charges are opposite and unlike.

<u>For Example:</u>

If we rub an iron rod with a cotton cloth, a positive charge will be induced in the iron rod and a negative charge will be induced in the cotton cloth. Note that the charges will be of equal magnitude.

$\rule[225]{225}{2}$

Hope this helped!

Let me know if you have any q's regarding this!

<h3>~AnonymousHelper1807</h3>

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4 years ago

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3 years ago

Two immersion heaters, A and B, are both connected to a 120.0-V supply. Heater A can raise the temperature of 1.00 L of water fr

Inessa05 [86]

Answer:

Ratio of resistance of heater A to resistance of heater B is 5.80

Explanation:

Consider C be the specific heat of water, R₁ and R₂ be the resistance of heater A and heater B respectively.

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Q₁ = m₁C(T₁ - T₀) and

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Ratio of power used by both the heaters A and B is:

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$\frac{P_{1} }{P_{2} } =\frac{m_{1} }{m_{2} }$ ...(1)

The relation to determine electrical power for both heaters A and B are:

$P_{1}=\frac{V^{2} }{R_{1} }$ and

$P_{2}=\frac{V^{2} }{R_{2} }$

Here V is the voltage applied to both the heaters and is equal.

So, the ratio of electrical power of heaters is:

$\frac{P_{1} }{P_{2} } =\frac{R_{2} }{R_{1} }$ ....(2)

But according to the problem, the electrical power is converted into the thermal power. So,equation (1) and (2) are equal. Hence,

$\frac{m_{1} }{m_{2} } =\frac{R_{2} }{R_{1} }$

Substitute the suitable values in the above equation.

$\frac{1 }{5.80 } =\frac{R_{2} }{R_{1} }$

$\frac{R_{1} }{R_{2} }=5.80$

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3 years ago

Answer please urgent​

Answer please urgent