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dmitriy555 [2]
3 years ago
11

What is 58,000,000,000 estimated as the product of a single digit and a power of 10?

Mathematics
1 answer:
Marina CMI [18]3 years ago
6 0
Since we are estimating, round to 60,000,000,000. Now count how many decimal places you would have to move to the left to get to a single digit (until we get to 6.0). That will be your exponent...

6 × 10^10
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Hello
hjlf

Answer:

1/10

Step-by-step explanation:

1 + 1/2 = 1 1/2

1 - 1/8 = 7/8

1 + 1/5 = 1 1/5

1 - 1/3 = 2/3

1 + 1/10 = 1 1/10

One and one tenth is closest to one because one tenth is the smallest amount that would need to be added or taken away to get exactly one. Hope I helped!

4 0
3 years ago
Read 2 more answers
Can someone help me plz lol I can't figure this one out
lidiya [134]

4NO+6H_{2} O\Leftrightarrow4 NH _{3}+5O_{2}

Step-by-step explanation:

NO+H_{2} O\rightarrow NH _{3}+O_{2}

4NO+6H_{2} O\Leftrightarrow4 NH _{3}+5O_{2}

8 0
3 years ago
“Write an equation in standard form of the horizontal line that goes through (-7, 10)”
OlgaM077 [116]

Answer:

Step-by-step explanation:

A horizontal line is only concerned with the y value. The equation is y = 10 because that is the point that the line must go through.

The x value does not matter as long as the y value is given as 10. The domain is any real value. The range is 10

6 0
3 years ago
Erin had 55 stuffed bears. She took out her favorite 7 bears and then equally divided the other bears among her 3 sisters. Erin'
Pavel [41]

Answer:

27 stuffed bears

Step-by-step explanation:

Erin: 55   Su: 15

Erin: 55-7=48 ( 7 will be kept for herself)

Erin and her sisters: 48/4= 12

Each sister besides Erin and Su have 12

Su: 15+12=27

Thus, Su will have 27 stuffed bears

3 0
3 years ago
Read 2 more answers
Find the vertices and foci of the hyperbola with equation quantity x plus 4 squared divided by 9 minus the quantity of y minus 5
My name is Ann [436]

Answer:

Vertices at (-7, 5) and (-1, 5).

Foci at (-9, 5) and (1,5).

Step-by-step explanation:

(x + 4)²/9 - (y - 5)²/16 = 1

The standard form for the equation of a hyperbola with centre (h, k) is

(x - h²)/a² - (y - k)²/b² = 1

Your hyperbola opens left/right, because it is of the form x - y.

Comparing terms, we find that

h = -4, k = 5, a = 3, y = 4

In the general equation, the coordinates of the vertices are at (h ± a, k).

Thus, the vertices of your parabola are at (-7, 5) and (-1, 5).

The foci are at a distance c from the centre, with coordinates (h ± c, k), where c² = a² + b².

c² = 9 + 16 = 25, so c = 5.

The coordinates of the foci are (-9, 5) and (1, 5).

The Figure below shows the graph of the hyperbola with its vertices and foci.

6 0
4 years ago
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